Population of moose in the national park = 240
percentage increase in the population of moose in the national park after a year = 25%
Then
Amount of increase in the population
Of moose in the national park in a year = (25/100) * 240
= 240/4
= 60
So
The number of moose present after 1 year
in the national park = 240 + 60
= 300
So from the above deduction we can easily conclude that the number of moose in the national park after a year is 300.
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer:
C
Step-by-step explanation:
120 *.3 = 36
120-36 = 84
84*.3 = 25.2
84-25.2= 59.8
120*.6 = 72
120-72 = 48
59.8-48 = 10.8 C
Answer:
166 marbles
Step-by-step explanation:
O - 44 = L
O - 48 = J
O - 6 = L + J
I want to isolate O here
O = 44 + L
Plug it in
44 + L - 6 = L + J
38 + L = L + J
38 = J
Now we know that Jack has 38.
O - 48 = J
O - 48 = 38
O = 86
Now we know Oscar has 86.
O - 44 = L
86 - 44 = L
42 = L
Lily has 42.
38 + 86 + 42 = .....166
They have 166 coins altogether - Also Happy New Year!!! :D
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