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3 years ago

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Solve the triangle. Round your answers to the nearest tenth. law of sines 7 A. m∠A=48, m∠B=50, a=23 B. m∠A=48, m∠B=50, a=26 C. m

∠A=43, m∠B=55, a=16 D. m∠A=43, m∠B=55, a=20

1 answer:

Anit [1.1K]3 years ago

6 0

Answer:

hsjjsgsuaigdhwishegiahdywiah

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-(y + 2) + 8 = 3<br> I’m so confused on this, please send help

Hoochie [10]

Don't be worried friend :)

-(y + 2) + 8 = 3

=> -(y + 2) = -5

=> y + 2 = 5

=> y = 3

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3 years ago

A line represented by y = 2x − 3 and a line perpendicular to it intersect at R(2, 1). What is the equation of the perpendicular

neonofarm [45]

Answer:

y = -1/2x + 2

Step-by-step explanation:

y = 2x - 3. The slope here is 2. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal, just flip the slope and change the sign.

slope = 2 or 2/1.....flip it.....1/2....change the sign...-1/2. So our perpendicular line will have a slope of -1/2.

y = mx + b

slope(m) = - 1/2

(2,1)....x = 2 and y = 1

now we sub and find b, the y intercept

1 = -1/2(2) + b

1 = -1 + b

1 + 1 = b

2 = b

so ur equation is : y = -1/2x + 2 <===

and u can check it with ur points....(2,1)

y = 2x - 3

1 = 2(2) - 3

1 = 4 - 3

1 = 1 (yep...it checks out)

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3 years ago

The perimeter of a square is 40 inches...Determine the area of the square ... A.) 160 square inches B) 10 square *inches C) 100

marysya [2.9K]

P=4s

s=p/4

a=s^2, using s found above

a=p^2/16, we were told that p=40 so

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4 0

3 years ago

Please help! serious answers only

vovangra [49]

I believe also 115 degrees bc they’re vertical angles

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2 years ago

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Suppose the number of births that occur in a hospital can be assumed to have a Poisson distribution with parameter = the average

arsen [322]

Answer:

0.5372

Step-by-step explanation:

Given that the number of births that occur in a hospital can be assumed to have a Poisson distribution with parameter = the average birth rate of 1.8 births per hour.

Let X be the no of births in the hospital per hour

X is Poisson

with mean = 1.8

the probability of observing at least two births in a given hour at the hospital

= $P(X\geq 2)\\= 1-F(1)\\= 1-0.4628\\= 0.5372$

the probability of observing at least two births in a given hour at the hospital = 0.5372

4 0

3 years ago