I need help with my algebra h.w.
1 answer:
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Answer with explanation:
Volume of a solid right pyramid with a square base = V (units)³
-------------------------------------(1)
The <u>Solid right pyramid will be in the shape of Cube</u>.
Length of edge of Right Pyramid = y units
So,Volume of Right Pyramid which is in the shape of Cube
= (Side)³
=y³ (Units)³
---------------------------------(2)
Equating (1) and (2)
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
A cylinder shaped water pitcher has a radius of 5 inches and a height of 12.5 inches. Find the surface area of the pitcher.
<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2><h3>Given:-</h3> Radius (r) of a cylinder shaped water pitcher = 5 inches.
Height (h) of a cylinder shaped water pitcher = 12.5 inches.
The surface area of the pitcher.
<h2>Solution:-</h2>We know,
Formula of Surface area of a cylinder is 2πr(r + h) sq. units.
So,
Surface area of the pitcher = 2 × 3.14 × 5(5 + 12.5)
Surface area of the pitcher = 31.4 × 17.5
Surface area of the pitcher = 549.5 in²
The surface area of the pitcher is <u>5</u><u>4</u><u>9</u><u>.</u><u>5</u><u> </u><u>i</u><u>n</u><u>²</u>.
Hence, the option (C) <u>5</u><u>4</u><u>9</u><u>.</u><u>5</u><u> </u><u>i</u><u>n</u><u>²</u> is correct. [Answer]
For this case we have:
Let be a given function, where:
- x is an independent variable
- y it is a dependent variable
By definition, the domain of a function is represented by the values associated with the independent variable, that is, the values of x.
Therefore, the domain of the given function is represented by:
Answer: