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2 years ago

A market research company located in a mall decides to survey people about their shopping habits. They ask customers coming into

Mathematics

2 answers:

sattari [20]2 years ago

7 0

Is biased because they are coming to the store which means they most likely prefer that

ladessa [460]2 years ago

5 0

Answer:

Step-by-step explanation:

the method of sampling is biased

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The senior classes at High School A and High School B planned separate trips to Lake Compounce. The senior class at High School

storchak [24]

Answer:

Number of students in vans =15 and bus =46

Step-by-step explanation:

use variables for the vans and buses

let x= vans and y=buses

Now solve the 2 equations simultaneously

remember to number your equations

6x+7y=412..........1

6x+9y=504.........2

make x the subject of one equation

and label it equation 3

6x=412—7y

$x = \frac{206}{3} - \frac{7y}{6} .............3$

subs 3 into 2

$6( \frac{206}{3} - \frac{7y}{6} ) + 9y = 504$

$412 - 7y + 9y = 504$

$- 7y + 9y = 504 - 412$

$2y = 92$

$y = 46...................4$

subs 4 into 1

$6x + 7(46) = 412$

$6x + 322 = 412$

$6x = 412 - 322$

$6x = 90$

$x = 15$

Therefore there are 15 students in each van and 46 students in each bus.

3 0

2 years ago

Which of the following operations is true regarding relative frequency distributions? Multiple choice question. No two classes c

pshichka [43]

Answer:

The relative frequency is found by dividing the class frequencies by the total number of observations

Step-by-step explanation:

Relative frequency measures how often a value appears relative to the sum of the total values.

An example of how relative frequency is calculated

Here are the scores and frequency of students in a maths test

Scores (classes) Frequency Relative frequency

0 - 20 10 10 / 50 = 0.2

21 - 40 15 15 / 50 = 0.3

41 - 60 10 10 / 50 = 0.2

61 - 80 5 5 / 50 = 0.1

81 - 100 10 10 / 50 = 0.2

50 1

From the above example, it can be seen that :

two or more classes can have the same relative frequency
The relative frequency is found by dividing the class frequencies by the total number of observations.
The sum of the relative frequencies must be equal to one
The sum of the frequencies and not the relative frequencies is equal to the number of observations.

4 0

2 years ago

John has taken out a loan for college. He started paying off the loan with a first payment of $100. Each month he pays, he wants

sergeinik [125]

Let a_0 = 100, the first payment. Every subsequent payment is the prior payment, times 1.1. In order to represent that, let a_n be the term in question. The term before it is a_n-1. So a_n = 1.1 * a_n-1. This means that a_19 = 1.1*a_18, a_18 = 1.1*a_17, etc. To find the sum of your first 20 payments, this sum is equal to a_0+a_1+a_2+...+a_19. a_1 = 1.1*a_0, so a_2 = 1.1*(1.1*a_0) = (1.1)^2 * a_0, a_3 = 1.1*a_2 = (1.1)^3*a_3, and so on. So the sum can be reduced to S = a_0 * (1+ 1.1 + 1.1^2 + 1.1^3 + ... + 1.1^19) which is approximately $5727.50

8 0

2 years ago

Which scatter plot would have a trend line with a negative y-intercept?

emmasim [6.3K]

Answer:

Step-by-step explanation:

8 0

2 years ago

Which of the following data sets represents a positive correlation?

Papessa [141]

The answer would be B, because it has a general upward slope

4 0

3 years ago

Read 2 more answers