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2 years ago

How do I do this problem? Evaluate each expression (-4)-(-6)-(2-1)

Mathematics

1 answer:

natita [175]2 years ago

6 0

Answer:

Step-by-step explanation:

(-4) - (-6) - (2-1)

-4 + 6 -2 +1

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HURRY PLEASE I WILL GIVE BRAINLIEST AND LOTS OF POINTS

Mrac [35]

Answer:

$m = \dfrac{3}{4}$

Step-by-step explanation:

We would like to find the slope of the line of the given equation .

$\longrightarrow y =\dfrac{3}{4}x -1$

We know that slope intercept form of the line is given by ,

$\longrightarrow y = mx + c$

where ,

m is the slope
c is y intercept

Now we can compare the given equation with the slope intercept form to find the slope . You will see that 3/4 is present at the place of m .Therefore ,

$\longrightarrow \underline{\underline{m=\dfrac{3}{4}}}$

Hence option C is correct choice .

4 0

1 year ago

Write 3x + 8x3 + 15 + 4x2 in standard form

Nadusha1986 [10]

Answer:

gcdshdgkcggcucjdchgjjkdcbkbdw

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

on a map, the length of a nature center Trail is 6.5 cm. If the scale is 2 cm to 10 km oh, what is the actual Trail? BRAINLY

mash [69]

Answer:

32.5 km

Step-by-step explanation:

6.5 / 2 = 3.25

3.25 x 10 = 32.5 km

Hope that helps!

6 0

2 years ago

Read 2 more answers

A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions

salantis [7]

Dimensions are length 20 meter and width 14 meter

Solution:

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

A rectangle has width that is 6 meters less than the length

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

The area of the rectangle is given by formula:

$Area = length \times width$

Substituting the values we get,

$Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0$

Solve the above equation by quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}$

$a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14$

Since, length cannot be negative, ignore a = -14

Thus solution of length is a = 20

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0

3 years ago

Which shows the equation 3y – x = 6 written in slope-intercept form?

laila [671]

Slope intercept form : y = mx + b

3y - x = 6 ....add x to both sides
3y = x + 6 ...divide both sides by 3
y = x/3 + 2 <== slope intercept form

7 0

3 years ago