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Anuta_ua [19.1K]
3 years ago
11

Suppose that the Dallas School District wants to achieve Six Sigma quality levels of performance in delivering students to schoo

l. They have established a 20-minute window as an acceptable range within which buses carrying students should arrive at school. a. What is the maximum allowable standard deviation of arrival times required in order to achieve this standard of quality? (Round your answer to 2 decimal places.) b. If they achieve this standard, about how many times out of a million deliveries will a bus deliver students either too early or too late? (Round your answer to 1 decimal place.)

Business
1 answer:
Kay [80]3 years ago
8 0

Answer:

a) 1.66 minutes

b) 3.4 out of million deliveries

Explanation:

So, it is a six sigma quality question, we first need to understand little bit about six sigma and how it is to achieve six sigma level.

<u>Six Sigma:</u>

It is the process or technique used by many organizations through out the world to achieve maximum quality in a product or in a service they are providing. It helps to indicate root causes of the process or you can say waste steps which first need to be identified then rectified to bring that top-notch quality in the system. So in this case, in order to calculate part a) we will calculate six sigma control limits.

a) So, for six sigma control limits, the maximum allowable standard deviation is 12 or you can say +6 + (-6) = ±6 = 12. It means all deviations must lie in all 12 standard deviations.

<em>Please refer to the table shown in the attachment.</em> This bell curve represent six sigma concept. In this <em>3 sigma quality level means all deviations must lie in 6 standard deviations.</em>

So, here we have been given that mean = 20, so with mean we can calculate standard deviation in six sigma control limits.

Maximum Allowable Standard Deviation for 6 sigma = Mean/12

                                                                                        = 20/12

                                                                                       = 1.66

So, 1.66 is the maximum allowable standard deviation of arrival times required in order to achieve 6 sigma quality level.

b) In this part, we are asked that, out of million deliveries about how many times bus deliver students too early or too late at this 6 sigma quality level.

<em>For this answer, please refer to attachment again</em>. and notice at the left bottom with the arrow of 6 sigma, we have a number 3.4 ppm means 3.4 part per million.

<em>So, it 3.4 times in a million deliveries bus will deliver students either too early or too late. </em>

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Answer:

Options C and E

Only Nick and Jake are optimising over his choice of fruit?

Explanation:

The marginal utility obtained from the purchase of a product is the amount of satisfaction derived from purchasing an additional unit of the product.

The utility is maximised when the satisfaction in terms of marginal utilities obtained from each product is equal to each other.

We obtain this simply by dividing the marginal utilities for each fruit by their price, and comparing them.

Dmitiri:

Apples: 8/1 =8

Pears: 10/2 =5

8/1 is not equals to 10/2

Frances:

Apples: 7/1 =7

Pears: 16/2 =8

7 is not equals to 8

Jake:

Apples: 6/1 =6

Pears: 12/2 =6

The marginal utility is equal hence Jake's choice is optimal

Latasha:

Apples: 5/1 =9

Pears: 9/2 =4.5

9 is not equals to 4.5

Nick:

Apples: 4/1 =4

Pears: 8/2 =4

The marginal utility is equal hence Nick's choice is optimal

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3 years ago
Funsters, Inc., the largest toy company in the country, sells its most popular doll for $15. It has just learned that its leadin
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Funsters should increase the supply of its doll now before the other doll hits the market.

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Suppose the Environmental Protection Agency (EPA) wants to mandate that all methane emissions must be reduced to zero in order t
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Answer:

C

Explanation:

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8 0
3 years ago
A shop that makes candles offers a blueberry scented candle which has daily demand of 10 boxes. Blueberry candles can be produce
Lostsunrise [7]

Answer:

E. 115 boxes.

Explanation:

d: 10 boxes/day

p: 36 boxes/day

n: 365 days

s: $60

H: $24 box/year

D: d*n

D= 10*365= 3650 boxes/year

EPQ = \sqrt{2DS/H} *\sqrt{p/p-d}

EPQ=\sqrt{2*365*60/24} *\sqrt{36/36-10}  

EPQ= 158.96 = 159 units

I=Q/P * (p-d)

I=159/36 * (36-10)

I=114.83

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7 0
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Effective annual rate: Raj Krishnan bought a Honda Civic for $17,345. He put down $6,000 and financed the rest through the deale
g100num [7]

Answer:

EAR = 5.01%

Explanation:

Given that

APR = 4.9% = 0.049

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= 11,345

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Recall that

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= 1+ 0.049/12^12 - 1

= 1.0501 - 1

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