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Fudgin [204]
3 years ago
9

Using six bits, Show the binary counting sequence from 000000 to 111111

Engineering
1 answer:
fenix001 [56]3 years ago
8 0

Answer:

Explanation:

The least significant unit bits switch from 0 → 1 or 1 → 0 with each count.

The next bit(two-position) which is the second bit usually be at 0s for two counts and at  1s at two counts. The third bit (four positions) usually be at 0s for four counts and then at 1 for four counts. etc. The fourth bit (eight positions) usually be at 0s for eight counts and then at 1 for eight counts and so on. The fifth bit (sixteen positions) usually be at 0s for sixteen counts and then at 1 for sixteen counts and so on. The sixth bit (thirty-two positions) usually be at 0s for thirty-two counts and then at 1 for thirty-two counts and so on in the sequence of six-bit binary counting.

From the document attached below, we can see a document file showing the binary counts sequences from 000000 to 111111.

Download docx
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Explanation:

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A rigid, insulated tank that is initially evacuated is connected through a valve to a supply line that carries helium at 200 kPa
Aleks04 [339]

Answer: a 8143.71 kJ/kg

b 393.15 K

Explanation:

This system is an isobaric process in which there is no change in pressure a quasistatic process where a pressure distribution exists

a since no change in pressure =0 the system does work thus

FOR HELIUM  properties in standard thermodynamic chart

cv = 3.1 kJ/kgK

M = Molar mass = 4 kg/kmol

R = Universal gas constant = 8.314 kJ/kg K

cp ≈ cv +R /M = 3.1 + 8.314 /4 = 5.1785 kJ/kgK  

Cp = cp * M = 5.1785 kJ/kgK * 4 kg/kmol  = 20.714 kJ/kgkmol

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W =n Cp ΔT = 1 kmol * 20.714 kJ/kg kmol* 393.15 K = 8143.71 kJ/kg

b convert T °C = T K thus 120 + 273.15 K = 393.15 K

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7 0
4 years ago
HW6P2 (20 points) The recorded daily temperature (°F) in New York City and in Denver, Colorado during the month of January 2014
Maurinko [17]

Answer & Explanation:

function Temprature

NYC=[33 33 18 29 40 55 19 22 32 37 58 54 51 52 45 41 45 39 36 45 33 18 19 19 28 34 44 21 23 30 39];

DEN=[39 48 61 39 14 37 43 38 46 39 55 46 46 39 54 45 52 52 62 45 62 40 25 57 60 57 20 32 50 48 28];

%AVERAGE CALCULATION AND ROUND TO NEAREST INT

avgNYC=round(mean(NYC));

avgDEN=round(mean(DEN));

fprintf('\nThe average temperature for the month of January in New York city is %g (F)',avgNYC);

fprintf('\nThe average temperature for the month of January in Denvar is %g (F)',avgDEN);

%part B

count=1;

NNYC=0;

NDEN=0;

while count<=length(NYC)

   if NYC(count)>avgNYC

       NNYC=NNYC+1;

   end

   if DEN(count)>avgDEN

        NDEN=NDEN+1;

   end

   count=count+1;

end

fprintf('\nDuring %g days, the temprature in New York city was above the average',NNYC);

fprintf('\nDuring %g days, the temprature in Denvar was above the average',NDEN);

%part C

count=1;

highDen=0;

while count<=length(NYC)

   if NYC(count)>DEN(count)

       highDen=highDen+1;

   end

   count=count+1;

end

fprintf('\nDuring %g days, the temprature in Denver was higher than the temprature in New York city.\n',highDen);

end

%output

check the attachment for additional Information

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4 years ago
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salantis [7]

Answer:

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