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2 years ago

If my current directory is ‘AR’ write the path for my current directory

Engineering

1 answer:

salantis [7]2 years ago

6 0

Answer:

sorry not having idea about answer

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A subsurface exploration report shows that the average water content of a fine-grained soil in a proposed borrow area is 22% and

Morgarella [4.7K]

Answer:

shrinkage ratio = 1.538

Explanation:

given data

water content = 22 %

dry density γ = 82 pcf

required dry density specified γ' = 96 pcf

required to produce = 50,000 yd³ = 50000 × 27 = 1350,000 ft³

solution

we get here first volume of borrow pit that is we know that

dry density ∝ $\frac{1}{volume}$

so $\frac{\gamma d}{\gamma 'd} = \frac{v'}{v}$

$\frac{82}{96} = \frac{1350000}{v}$

v = 1580487.8 ft³

v = 58536.58 yd³

so here

shrinkage ratio will be as

shrinkage ratio = $\frac{96}{62.4}$

shrinkage ratio = 1.538

6 0

2 years ago

Where do I buy a 1997 MK4 Toyota Supra twin turbo manual for cheap

MA_775_DIABLO [31]

Idk what that means i’m sorry

6 0

2 years ago

A pulse-jet baghouse is desired for a finished cement plant. Calculate the number of bags required to filter 500 m3/min of air w

omeli [17]

Answer:

1) 4.41 * 10^-4 kw

2) 2.20 * 10^-4 kw

Explanation:

Given data:

Filter = 500 m^3/min

dust velocity = 3g/m^3

bag ; length = 3 m , diameter = 0.13 m

change in pressure = 1 kPa

efficiency = 60%

1) Calculate the Fan power

First :

Calculate the total dust loading = 3 * 500 = 1500 g

To determine the Fan power we will apply the relation

$n_{o} = \frac{\frac{p}{eg*Q*h} }{1000}$ = $\frac{\frac{p}{(3*10^{-3})* 981*( 500/60) *3 } }{1000}$

fan power ( $n_{0}$ ) = 4.41 * 10^-4 kw

2) calculate power drawn

change in P = 6 atm = 6 * 10^5 pa

efficiency compressor = 50%

hence power drawn = 4.41 * 10^-4 kw * 50% = 2.20 * 10^-4 kw

3 0

3 years ago

A car is traveling at 36 km/h on an acceleration lane to a freeway. What acceleration is required to obtain a speed of 72 km/h i

dmitriy555 [2]

First, write down the information given and the change units if necessary (we must have similar units to operate on).

Initial speed, u = 36 km/h = 10 m/s

Final speed, v = 72 km/h = 20 m/s

Distance, s = 100 m

We know that

${v}^{2} - {u}^{2} = 2as \\ {20}^{2} - {10}^{2} = 2 \times a \times 100 \\ 400 - 100 = 200 \times a \\ a = \frac{300}{200 } = \frac{3}{2} \: m {s}^{ - 2}$

Now, we substitute v, u, and a in the formula

$v = u + at \\ 20 = 10 + \frac{3}{2} t \\ \frac{3}{2} t = 10 \\ 3t = 20 \\ t = \frac{20}{3} = 6.67 \: seconds$

Please mark Brainliest if this helps!

6 0

3 years ago

Okay bro let’s go man yes yes

r-ruslan [8.4K]

Sheeeeeesh bro same name ayoooo??

8 0

3 years ago

Read 2 more answers