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Dennis_Churaev [7]
3 years ago
5

If my current directory is ‘AR’ write the path for my current directory

Engineering
1 answer:
salantis [7]3 years ago
6 0

Answer:

sorry not having idea about answer

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What are the nominal dimensions for a 1x2 stick of lumber, a 2x4 stick of lumber and a standard sheet of plywood?
zlopas [31]
3/4 x 1 1/2 inches (19 x 38 mm) is the actual size for 1x2 stick of lumber,

1 1/2 x 3 1/2 inches (38 x 89 mm) is the actually size for a 2x4 stick of lumber,

Plywood is usually sold in 4 x 8-foot sheets. The most common nominal thicknesses of plywood are 1/2 inch and 3/4 inch, but once again the actual sizes are slightly different. A sheet of 1/2-inch plywood is really 15/32 inch thick, while a 3/4-inch sheet is 23/32 inch thick.

Hopefully this answers your question, I apologize if it doesn’t :)
6 0
3 years ago
A) If a given directional antenna can receive 15 times the power of an isotropic antenna, what is
Sauron [17]

The gain of the directional antenna is calculated based on the comparison

with an hypothetical isotropic antenna.

  • a) The gain in dBi of the isotropic antenna is approximately <u>11.76 dBi</u>
  • b) The power received by the isotropic antenna is approximately <u>0.61 mW</u>

Reasons:

a) The number of times the power of the directional antenna is stronger than the  isotropic antenna, G = 15 times

The gain in dBi is given as follows;

\displaystyle G = \mathbf{10^{\dfrac{G(dBi)}{10} }}

Which gives;

\displaystyle 15 = 10^{\dfrac{G(dBi)}{10} }

\displaystyle \dfrac{G(dBi)}{10}  = \frac{ln(15)}{ln(10)}

\displaystyle G(dBi)} = 10 \times \frac{ln(15)}{ln(10)} \approx 11.76

The power gain of the isotropic antenna, G(dBi) ≈ <u>11.76 dBi</u>

b) When the gain of the directional antenna is 2.15 dBi and it received 1 mW of power, we have;

The number of times stronger the directional antenna is, is found as follows;

\displaystyle G  = 10^{\dfrac{2.15}{10} } \approx \mathbf{1.64}

The 2.15 dBi directional antenna receives the signal approximately 1.64 times stronger than the isotropic antenna, therefore;

  • \displaystyle The \ power \ received \ by \ the \ isotropic \ antenna  = \frac{1 \, mW}{1.64}  \approx \underline {0.61 \, mW}

Learn more here:

brainly.com/question/17587029

4 0
3 years ago
Blank Complete the following paragraph pertaining to the popular audio file formats.
erastova [34]

Answer:

So #1 is A and #2 is c.

Explanation:

<u><em>#1.  </em></u>MP3 (MPEG-1 Audio Layer-3) is a standard technology and format for compression a sound sequence into a very small file (about one-twelfth the size of the original file) while preserving the original level of sound quality when it is played.

<u><em>#2.</em></u> AIFF (Audio Interchange File Format) is one of the two most-used audio file formats used in the Apple Macintosh operating system. The other is Sound Designer II (SDII). ... An AIFF file contains the raw audio data, channel information (monophonic orstereophonic), bit depth, sample rate, and application-specific data areas.

7 0
4 years ago
Read 2 more answers
How much energy does it take to boil water for pasta? For a one-pound box of pasta
ArbitrLikvidat [17]

Answer:

a.  164 °F b. 91.11 °C c. 1439.54 kJ

Explanation:

a. [1 pts] How many degrees Fahrenheit (°F) must you raise the temperature?

Since the starting temperature is 48°F and the final temperature which water boils is 212°F, the number of degrees Fahrenheit we would need to raise the temperature is the difference between the final temperature and the initial temperature.

So, Δ°F = 212 °F - 48 °F = 164 °F

b. [2 pts] How many degrees Celsius (°C) must you raise the temperature?

To find the degree change in Celsius, we convert the initial and final temperature to Celsius.

°C = 5(°F - 32)/9

So, 48 °F in Celsius is

°C₁ = 5(48 - 32)/9

°C₁ = 5(16)/9

°C₁ = 80/9

°C₁ = 8.89 °C

Also, 212 °F in Celsius is

°C₂ = 5(212 - 32)/9

°C₂ = 5(180)/9

°C₂ = 5(20)

°C₂ = 100 °C

So, the number of degrees in Celsius you must raise the temperature is the temperature difference between the final and initial temperatures in Celsius.

So, Δ°C = °C₂ - °C₁ = 100 °C - 8.89 °C = 91.11 °C

c. [2 pts] How much energy is required to heat the four quarts of water from

48°F to 212°F (boiling)?

Since we require 15.8 kJ for every degree Celsius of temperature increase of the four quarts of water, that is 15.8 kJ/°C and it rises by 91.11 °C, then the amount of energy Q required is Q = amount of heat per temperature rise × temperature rise =  15.8 kJ/°C × 91.11 °C = 1439.54 kJ

8 0
3 years ago
6. PVC boxes are primarily used in new construction because it is simple to
Umnica [9.8K]
Simply rafters because of the pvc boxes are brittle and they need support
3 0
3 years ago
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