You're about to make a measurement with an oscilloscope when you find that the trace appears to be very weak on the screen. Whic
2 answers:
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Answer:
•Estimated density = 39.685Pc/mi/en
•Level of service, LOS frequency = LOSC
Explanation:
We are given:
•Freeway current lane width,B = 12ft
• freeway current shoulder width,b = 6ft
• percentage of heavy vehicle, Ptb = 10℅
• peak hour factor, PHF = 0.9
Let's consider,
•Number of lanes N = 4
• flow of traffic V = 7500vph
• percentage of Rv = 0, therefore the freeflow speed in freeway FFS = 70mph
• cars equivalent for recreational purpose Er= 2
•cars to be used for trucks and busses Etb= 2.5
Let's first calculate for the heavy adjustment factor.
We have:
Substituting figures in the equation we have:
= 0.75
Let's now calculate equivalent flow rate of the car using:
= 2777.7 pc/h/en
Calculating for traffic density, we have:
D = 39.685 Pc/mi/en
Using the table for LOS criteria of basic frequency segment, the level of service LOS of frequency is LOSC
Answer:
Follows are the solution to this question:
Explanation:
Calculating the area under the curve:
A = as
Calculating the kinematics equation:
Calculating the value of acceleration: