9514 1404 393
Answer:
625 square feet
Step-by-step explanation:
The greatest area of a polygon with a given perimeter is that of a regular polygon. A regular rectangle is one that has all sides the same length -- a square. The side length of a square with 100 ft perimeter is 25 ft. The area of a square with such a side length is
A = (25 ft)² = 625 ft²
The maximum possible area is 625 ft².
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In the attached, x is the length of one side. The area versus side length is plotted. The maximum is seen to be 625 ft² for a side length of 25 ft.
Answer:
A
Step-by-step explanation:
first lets find the area of the square
A=l*w
12*12=144 m^2
then lets find the are of the circle
A=pi*r^2
A=3.14*(d/2)^2
the diameter of the circle is 12m
A=3.14*(12/2)^2
A=3.14*(6)^2
A=3.14*36
A=113.04 m^2
Now, lets subtract the area of the circle form the area of the square
144-113.04= 30.96 m^2
So, the answer is A
Answer:
I think the answer is B
Explanation:
1.25x10 to the power of 7 =
12,500,000
I hope it helps!
Step-by-step explanation:
v=s^3 s=3^4=81
v=(81)^3
v=531,441 cm^3
2(3+3) or 2(3)+6, so the answer is the third option. It’s just using the distributive property.
