The first triangle is dilated to form the second triangle. Select True or False for each statement.

Mathematics

1 answer:

malfutka [58]2 years ago

3 0

Answer:

these are the step to follow so A=bh

Step-by-step explanation: A=1/2bh A=bh A=1/2 (b=b)h this is an example so you can follow how i did this

You might be interested in

A coin is tossed and an eight-sided die numbered 1 through 8 is rolled. Find the probability of tossing a head and then rolling

ratelena [41]

Answer: 7/8

Step-by-step explanation:

Probability is calculated by number of possible outcomes/ total outcomes

From the question, a coin only has two sides, Head or Tail. Total outcomes is therefore equal to 2

Possible outcome is to toss a head, which is one event

Probability of tossing a head is therefore =1/2

The second part of the question is rolling a die with eight sides.

Here, the die is said to have eight sides, 1,2,3,4,5,6,7,8. Total outcomes is therefore equal to 8

Possible outcome of rolling a number greater than 5 is 3 possibilities, that is rolling 6, 7 and 8.

Pr(rolling > 5) is 3/8

Therefore, Pr ( head; rolling > than 5)

= 1/2 + 3/8

=7/8

I hope this is clear, please mark as brainliest answer

6 0

3 years ago

The height of a tennis ball tossed into the air is modeled by h(x) = 40x â€" 16x 2, where x is elapsed time in seconds. During w

egoroff_w [7]

The time interval x >0.5 and x > 2.04 will the tennis ball be at least 15 feet above the ground.

Given that,

The height of a tennis ball tossed into the air is modeled by,

$\rm h(x) = 40x - 16x^2$

Where x is elapsed time in seconds.

We have to determine,

During what time interval will the tennis ball be at least 15 feet above the ground?

According to the question,

The height of a tennis ball tossed into the air is modeled by,

$\rm h(x) = 40x - 16x^2$

Where x is elapsed time in seconds.

Then,

When the tennis ball be at least 15 feet above the ground,

$h(x) = 15$

Substitute the value of h(x) in the equation,

$\rm h(x) = 40x - 16x^2\\\\ 15 = 40x - 16x^2\\\\ 16x^2-40x+15=0$

Factorize the equation for finding the time interval will the tennis ball be at least 15 feet above the ground is,

$\rm 16x^2-40x+15= 0\\\\x = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\x = \dfrac{-(-40)\pm \sqrt{(-40)^2-4 \times 16 \times 15}}{2 \times 16}\\\\x = \dfrac{-(-40)\pm \sqrt{1600- 960}}{32}\\\\x = \dfrac{40\pm \sqrt{640}}{32}\\\\x = \dfrac{40 + 25.29}{32} \\\\x = \dfrac{40 + 25.29}{32} \ and \ x = \dfrac{40 - 25.29}{32}\\\\x = \dfrac{65.29}{32} \ and \ x = \dfrac{14.71}{32}\\\\x = 2.04 \ and \ x = 0.45$