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Mashcka [7]
3 years ago
9

If a triangle can be formed with side lengths a, b, c and c^2 < a^2 + b^2, then the triangle is a(n) _________ triangle.

Mathematics
1 answer:
AleksAgata [21]3 years ago
3 0
The triangle is an acute triangle because of the Pythagorean Formula for acute triangles.
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B(n)=1 (-2)^n-1<br> What is the 4th term in the sequence
Vera_Pavlovna [14]

Answer:

The 4th term in the sequence is -8.

Step-by-step explanation:

The nth term of the sequence B is given by:

B(n) = (-2)^{n-1}

So the fourth term will be given by:

B when n = 4, that is, B(4).

B(4) = (-2)^{4-1} = (-2)^{3} = -8

The 4th term in the sequence is -8.

3 0
3 years ago
Someone please help out?
Delvig [45]
I dont know im trying to figure that out

7 0
3 years ago
The U.S.A. Olympic Synchronized Swimming Team is designing a routine for their upcoming competition. From the center of the pool
Mama L [17]

Answer:

The equation of the circle is;

(x - 2)² + (y - 4)² = 5²  

Step-by-step explanation:

We note that the general equation of a circle is given as follows;

(x - h)² + (y - k)² = r²

Where;

(h, k) = The coordinates of the center of the circle

r = The radius of the circle

The given parameters are;

The location of the center of the pool to the center of their formation = 2 feet to the right and 4 feet up from the center of the pool

The point through which the circle which they form goes through = A point 3 feet to the left and 4 feet up from the center of their formation

Taking the center of the pool as the origin of the coordinate plane system, we have;

The coordinate of the center of the circle = The coordinate of their motion from the center of the circle

∴ The coordinate of the center of the circle = (2, 4)

∴ (h, k) = (2, 4)

h = 2, k = 4

The coordinate of the point through which the circle passes = (2 - 3, 4 + 4) = (-1, 8)

∴ The length of the radius, 'r', can be found as, r = √((-3)² + 4²) = 5 or r = √((-1 - 2)² + (8 - 4)²) = 5

r = 5

The equation of the circle is therefore presented by substituting the values of 'h', 'k', and 'r', as follows;

(x - 2)² + (y - 4)² = 5².

4 0
3 years ago
Integrate t sec^2 (2t) dt
Neporo4naja [7]
F = t ⇨ df = dt 
dg = sec² 2t dt ⇨ g = (1/2) tan 2t 
⇔ 
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt 
u = 2t ⇨ du = 2 dt 

As integral of tan u = - ln (cos (u)), you get : 

integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant 
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant 
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer 
8 0
3 years ago
Read 2 more answers
Find the Solutions to these problems.
bezimeni [28]

I DON'T KNOW THE ANSWER BUT THANKS FOR THE POINT$

Step-by-step explanation:

I DON'T KNOW THE ANSWER BUT THANKS FOR THE POINT$

8 0
2 years ago
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