Question

write an equation of the line passing through (6,-5) parallel to a line with 4/3 .write the final answer in slope-intercept form​

Answer 1

The equation of line passing through (6,-5) and parallel to line with slope 4/3 is:

y=\frac{4}{3}x-13

Further explanation:

Given

Slope of line= 4/3

Point = (6,-5)

As the given line is parallel to the line whose slope is given. This means that the slope of the required line will be same as parallel lines have equal slope.

The general form of point-slope form is:

$y=mx+b$

Putting the value of slope

$y=\frac{4}{3}x+b$

To find the value of b, putting (6,-5) in equation

$-5=\frac{4}{3}(6)+b\\-5 = (4)(2)+b\\-5=8+b\\b=-5-8\\b=-13$

Putting the values of b and m

$y=\frac{4}{3}x-13$

The equation of line passing through (6,-5) and parallel to line with slope 4/3 is:

y=\frac{4}{3}x-13

Keywords: Point-slope form, Equation of line

Learn more about slope-intercept at:

• brainly.com/question/12858230
• brainly.com/question/12879138

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