Question

5x^(-2)-17x^(-1)+6 i’m so confused pls help will give brainliest

Answer 1

It's a quadratic equation in disguise. If you let $y=x^{-1}$, then $y^2=x^{-2}$, and we can rewrite the equation as

$5y^2-17y+6=0$

Solve for $y$ however you like; we get $y=\dfrac25$ and $y=3$.

But we want to solve for $x$, so we have

$y=x^{-1}=\dfrac25\implies x=\dfrac52$

$y=x^{-1}=3\implies x=\dfrac13$