V=4/3 πr^3would be the formula
Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
Answer:
B)
Step-by-step explanation:
Here, the given functions are:
Now, g(x) - h(x) is :
⇒
B) Hence,
The expression for the number of segments drawn out of the n number of points in the circle is,
n² / 2 - n / 2
Substituting directly to the expression the number of points, n, which is equal to 8,
8² / 2 - 8 / 2 = 28
Thus, there are 28 segments that can be drawn from the points.
Answer:
203
Step-by-step explanation:
17*7=119
12*7=84
84+119=203
