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Alchen [17]
3 years ago
5

0=5-2x+y solve the equation for y.

Mathematics
1 answer:
Makovka662 [10]3 years ago
5 0

Hello,

The answer for y is ) y=2x-5


How i got this?

1: Subtract 5 from both sides

2: add 2x to both sides

3: Divide both sides by -2 (to get y by it self)

4: flip the equation and you have your answer.


Hope this helps.

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Solve the following equation.-3 = x/5
Umnica [9.8K]
I hope this helps you




x/5= -3



x= -3.5



x= -15
7 0
3 years ago
Helpppppppppp!!! :( math up ):
HACTEHA [7]

Answer:

A 4/5 × 10 1/2 =8.4

B 2 1/2 × 16/5 =8

C 3 2/3 × 2 1/2 = 330/36 = 9.1666

D 20/3 × 9/10 =6

C IS THE GREATEST because 9.166 is greater than 8.4, 8 and 6

7 0
3 years ago
What value of m makes the equation true? m + 2m - 6 = -12 + 2m.
denpristay [2]

the answer is 6 i think

4 0
4 years ago
Read 2 more answers
Lucy is going to rent a truck for one day. There are two companies she can choose from, and they have the following prices
hram777 [196]

Answer: Any amount of milage more than 30

Step-by-step explanation: You can write an equation to compare the relationship between the costs that looks like:

102<75+0.9m

27=0.9m

m=30

4 0
2 years ago
Roberto rowed 20 miles downstream in 2.5 hours. The trip back, however, took him 5 hours. Find the rate that Roberto rows in sti
almond37 [142]

Answer:

<em>Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour</em>

Step-by-step explanation:

<u>Relative Speed</u>

When a body is moving at a constant speed v, the distance traveled in a time t is:

d=v.t

When Roberto rows downstream, his speed in still water is added to the speed of the water, making it easier to travel the required distance.

When Roberto rows upstream, his speed in still water is affected by the speed of the water, both are subtracted and the required distance is covered in more time.

Let's call

x = Roberto's rowing speed in still water

y = Speed of the river current

The speed when rowing downstream is x+y, thus the distance traveled is

d=(x+y).t_1

Where t1=2.5 hours. Substituting values:

20=(x+y)*2.5

Rearranging, we find the downstream equation:

2.5x+2.5y=20\qquad[1]

The speed when rowing upstream is x-y, and the distance traveled is

d=(x-y).t_2

Where t2=5 hours. Substituting values:

20=(x-y)*5

Rearranging, we find the upstream equation:

5x-5y=20\qquad[2]

Multiplying [1] by 2:

5x+5y=40

Adding this equation to [2]:

10x=60

Solving:

x=60/10=6

Dividing [2] by 5:

x-y=4

Solving for y

y=x-4=6-4=2

Thus, Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour

3 0
4 years ago
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