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oee [108]
2 years ago
8

2. A solar lease customer built up an excess of 6,500 kilowatt hours (kwh) during the summer using his solar

Mathematics
1 answer:
tia_tia [17]2 years ago
3 0

9514 1404 393

Answer:

  a)  E = 6500 -50d

  b)  5000 kWh

  c)  the excess will last only 130 days, not enough for 5 months

Step-by-step explanation:

<u>Given</u>:

  starting excess (E): 6500 kWh

  usage: 50 kWh/day (d)

<u>Find</u>:

  a) E(d)

  b) E(30)

  c) E(150)

<u>Solution</u>:

a) The exces is linearly decreasing with the number of days, so we have ...

  E(d) = 6500 -50d

__

b) After 30 days, the excess remaining is ...

  E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days

__

c) After 150 days, the excess remaining would be ...

  E(150) = 6500 -50(150) = 6500 -7500 = -1000 . . . . 150 days is beyond the capacity of the system

The supply is not enough to last for 5 months.

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6 0
1 year ago
Solve 4(2x-3)=6x+2<br> I don't understand the steps pls
Marysya12 [62]

Answer: x = 7

Step-by-step explanation:

4(2x-3) = 6x+2   <--distribute the 4

8x - 12 = 6x + 2   <---add 12 to both sides

8x = 6x + 14    <--- subrtract 6x from both sides

2x = 14    <--- divide by two

x = 7

6 0
3 years ago
4-2(3+2) ²<br> 2.<br> Help me plz i need the help
strojnjashka [21]

Answer:

-46 is your answer.

Step-by-step explanation:

=4-2(3+2)^2

=4-2(5)^2

=4-2(5✖️5)

=4-2(25)

Opening brackets to simplify

=4-50

=-46 is your answer.

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5 0
3 years ago
Read 2 more answers
Suppose that an airline uses a seat width of 16.7 in. Assume men have hip breadths that are normally distributed with a mean of
murzikaleks [220]

Answer:

Step-by-step explanation:

Given that X, the hip width of men is N(14.2, 0.9)

i.e. we have \frac{x-14.2}{0.9} is N(0,1)

Seat width an airline uses = 16.7 inches.

a) the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.7 in

=P(X>16.7 inches)\\= P(Z>\frac{16.7-14.2}{0.9} =P(Z>2.77)\\\\\\=P(Z>0)-(0

b) Here sample size = 126

Each person is independent of the other

the probability that these men have a mean hip breadth greater than 16.7

=0.0028^{126} <0.00001

c) part a is important since even a single person not fitting will cause embarassment and leads to customer dissatisfaction.

5 0
3 years ago
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Two tailors, Valentina and Laura, sit down to do some embroidery. Valentina can embroider 2 shirts per hour, and Laura can get t
mina [271]

Answer:

Valentina and Laura finished the same total number of shirts in 4 hours.

Total number of shirts finished by Valentina =23

Total number of shirts finished by Laura =23

Step-by-step explanation:

Suppose that Valentina and Laura finished the same total number of shirts in t hours.

Valentina can embroider 2 shirts per hour and Valentina has already completed 15 shirts.

Total number of shirts finished by Valentina =2t+15

Laura can get through 3 shirts per hour and Laura has completed 11 shirts.

Total number of shirts finished by Laura =3t+11

Therefore,

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So,

Valentina and Laura finished the same total number of shirts in 4 hours.

Total number of shirts finished by Valentina =2(4)+15=8+15=23

Total number of shirts finished by Laura =3(4)+11=12+11=23

6 0
3 years ago
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