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Eva8 [605]
3 years ago
12

Define a function that takes two arguments: a string called strText and a number called intNumber. This function will use a repe

tition structure (a While or For loop) to print strText intNumber of times. Call this function.
Computers and Technology
2 answers:
galben [10]3 years ago
6 0
<h2>Answer:</h2>

// Class declaration

public class Printer {  

   // Define the function and call it printMany

   // The return type is void since it doesn't necessarily return any value.

   // It just prints to the console.

   // It takes two arguments strText of type String and

   // intNumber of type int.

  public static void printMany(String strText, int intNumber){          

       // Initialize the loop counter i to 1;

       int i = 1;

      // Create a while loop that goes

      // from <em>i = 1</em> to  <em>i = intNumber</em>.

      // Where intNumber is the number of times the string strText

      // will be printed.

      while(i <= intNumber) {

           

            // At each of the cycle of the loop;

           // print out the string strText

           // and increment the value of the loop counter by 1

           System.out.println(strText);

           i++;

       }                 // End of while loop

   }               // End of method, printMany, declaration

// Write the main method to call the printMany function

public static void main(String[] args) {

       // Call the printMany function by supplying sample arguments;

       // In this case, strText has been given a value of "Omobowale"

       // And intNumber has been given a value of 4

       // Therefore, "Omobowale" will be printed 4 times.

       printMany("Omobowale", 4);

   }            //  End of main method

}          // End of class declaration

<h2>Sample Output: </h2>

<em>When the program above is run, the following will be the output;</em>

<em>----------------------------------------------------</em>

Omobowale

Omobowale

Omobowale

Omobowale

-------------------------------------------------------

<h2>Explanation:</h2>

Comments:

* The above code has been written in Java

* The code contains comments explaining every part of the code. Kindly go through the comments.

The whole code without comments is re-written as follows;

public class Printer {      

   public static void printMany(String strText, int intNumber){    

       int i = 1;

       while(i <= intNumber){

           System.out.println(strText);

           i++;

       }

   }      

   public static void main(String[] args) {

       printMany("Omobowale", 4);

   }

}

natima [27]3 years ago
3 0

Answer:

public class Main

{

   public static void printString(String strText, int intNumber) {

       for(int i=0; i<intNumber; i++){

           System.out.println(strText);

       }

   }

   

public static void main(String[] args) {

       

       printString("Brainly", 3);

}

}

Explanation:

- Define a function called <em>printString</em> that takes two parameters - a String and an int. Since the function will print out the given String, it's type will be <u>void</u>.

- Use <em>for loop</em> to iterate according to the given number and print the given string

- In the main, call the <em>printString </em>function with some parameters.

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3 0
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#Create a class called Name. Name should have two attributes
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Answer:

//class Name

class Name {

// attributes gave you 3

String first_name;

String last_name;

int length = 0;

//constructor with 2 parameters

Name(String first_name, String last_name){

}

//methods

public String find_printed_name(){

return first_name + " " + last_name;

}

public void find_sortable_name(){

return last_name + ", " first_name.charAt(0);

}

public static void main(String[] args){

// instantiate the class

Name test_name = new Name("David", "Joyner");

System.out.println(test_name.first_name);

System.out.println(test_name.last_name);

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System.out.println(test_name.find_sortable_name());

}

Explanation:

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3 0
3 years ago
*/ What's wrong with this program? /* public MyProgram { public static void main(String[] args); } int a, b, c \\ Three integers
gulaghasi [49]

Answer:

A lot is wrong with the program given in the question. See the corrected version below:

<em>public class ANot {</em>

<em>    public static void main(String[] args) {</em>

<em>        int a, b, c;</em>

<em>    //Three integers</em>

<em>    a = 3; b = 4; c = a + b;</em>

<em>        System.out.println("The value of c is " + c);</em>

<em>    }</em>

<em>}</em>

Explanation:

Errors:

1. The main method had a semi colon after it. This is wrong

2. An open brace was supposed to follow the main method

3. The declaration of the variables was supposed to end with a semi colon

4. the correct comment style is // and not \\

5. Initialization of variables was supposed to end with semi colons

6. The output statement had C and not c which is the declared and initialized variable..Java is strictly typed

7. Open and closing braces for the class and method wrongly placed

6 0
3 years ago
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