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Eva8 [605]
3 years ago
12

Define a function that takes two arguments: a string called strText and a number called intNumber. This function will use a repe

tition structure (a While or For loop) to print strText intNumber of times. Call this function.
Computers and Technology
2 answers:
galben [10]3 years ago
6 0
<h2>Answer:</h2>

// Class declaration

public class Printer {  

   // Define the function and call it printMany

   // The return type is void since it doesn't necessarily return any value.

   // It just prints to the console.

   // It takes two arguments strText of type String and

   // intNumber of type int.

  public static void printMany(String strText, int intNumber){          

       // Initialize the loop counter i to 1;

       int i = 1;

      // Create a while loop that goes

      // from <em>i = 1</em> to  <em>i = intNumber</em>.

      // Where intNumber is the number of times the string strText

      // will be printed.

      while(i <= intNumber) {

           

            // At each of the cycle of the loop;

           // print out the string strText

           // and increment the value of the loop counter by 1

           System.out.println(strText);

           i++;

       }                 // End of while loop

   }               // End of method, printMany, declaration

// Write the main method to call the printMany function

public static void main(String[] args) {

       // Call the printMany function by supplying sample arguments;

       // In this case, strText has been given a value of "Omobowale"

       // And intNumber has been given a value of 4

       // Therefore, "Omobowale" will be printed 4 times.

       printMany("Omobowale", 4);

   }            //  End of main method

}          // End of class declaration

<h2>Sample Output: </h2>

<em>When the program above is run, the following will be the output;</em>

<em>----------------------------------------------------</em>

Omobowale

Omobowale

Omobowale

Omobowale

-------------------------------------------------------

<h2>Explanation:</h2>

Comments:

* The above code has been written in Java

* The code contains comments explaining every part of the code. Kindly go through the comments.

The whole code without comments is re-written as follows;

public class Printer {      

   public static void printMany(String strText, int intNumber){    

       int i = 1;

       while(i <= intNumber){

           System.out.println(strText);

           i++;

       }

   }      

   public static void main(String[] args) {

       printMany("Omobowale", 4);

   }

}

natima [27]3 years ago
3 0

Answer:

public class Main

{

   public static void printString(String strText, int intNumber) {

       for(int i=0; i<intNumber; i++){

           System.out.println(strText);

       }

   }

   

public static void main(String[] args) {

       

       printString("Brainly", 3);

}

}

Explanation:

- Define a function called <em>printString</em> that takes two parameters - a String and an int. Since the function will print out the given String, it's type will be <u>void</u>.

- Use <em>for loop</em> to iterate according to the given number and print the given string

- In the main, call the <em>printString </em>function with some parameters.

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Which statement about intellectual property is true? (CSI-7.6) Group of answer choices It is okay to use code you find on the in
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Answer:

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Explanation:

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6 0
3 years ago
a.Write a Python function sum_1k(M) that returns the sum푠푠= ∑1푘푘푀푀푘푘=1b.Compute s for M = 3 by hand and write
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Answer:

def sum_1k(M):

   s = 0

   for k in range(1, M+1):

       s = s + 1.0/k

   return s

def test_sum_1k():

   expected_value = 1.0+1.0/2+1.0/3

   computed_value = sum_1k(3)

   if expected_value == computed_value:

       print("Test is successful")

   else:

       print("Test is NOT successful")

test_sum_1k()

Explanation:

It seems the hidden part is a summation (sigma) notation that goes from 1 to M with 1/k.

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White raven [17]

Answer:

#include <iostream>//including libraries

using namespace std;

int main()

{

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int secArr[7];//second array (1 element bigger)

for (int i = 0;i < 6;i++)//looping through each element (6 times)

{

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}

return 0;//terminating program

}

Explanation:

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