The term used to describe whereby old and new media are available via the integration of personal computers and high speed satellite based phone or cable links is: media convergence.
<h3>What's a good illustration of media convergence? </h3>
- Smartphones, laptops, and ipads are the finest instances of media convergence since they combine several forms of digital media, including radio, cameras, TVs, music, and more, into a single, straightforward gadget.
- The blending of formerly separate media platforms and technologies through digitization and computer networking is referred to as media convergence. Another name for this is technical convergence.
- Media ownership concentration, sometimes referred to as media consolidation or media convergence, is the process through which a smaller number of people or organisations come to control a larger portion of the mainstream media.
- According to recent study, there is a rising amount of consolidation in the media sectors, which are already highly concentrated and controlled by a very limited number of companies.
To learn more about media convergence, refer to the following link:
brainly.com/question/25784756
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D) Alt Tags thats the answer i think
Answer: Azzam used the tool while he was on the third page
Explanation:
The most likely the reason why the phrase was not fixed is because Azzam used the tool while he was on the third page.
This can be infered from the information given when we're told that he uses the Find and Replace tool and clicks on "Replace All" to fix the issue with regards to the error that he made and thus was done from the third page. Therefore, the tool might not have worked for the first page.
Answer:
In C++:
#include <bits/stdc++.h>
#include <iostream>
#include <vector>
using namespace std;
int main(){
vector<int> vectItems;
cout << "Vector length: ";
int ln; cin>>ln;
int num;
for (int ikk = 0; ikk < ln; ikk++){
cin >> num;
vectItems.push_back(num);}
int small, secsmall;
small = secsmall = INT_MAX;
for (int ikk = 0; ikk < ln; ikk++){
if(vectItems[ikk] < small){
secsmall = small;
small = vectItems[ikk]; }
else if (vectItems[ikk] < secsmall && vectItems[ikk] != small) {
secsmall = vectItems[ikk];} }
cout<<small<<" "<<secsmall;
return 0;}
Explanation:
See attachment for program file where comments are used for explanation