2 years ago

Midpoint of the x intercepts of f(x)=(x-4)(x+4)

Mathematics

2 answers:

faltersainse [42]2 years ago

6 0

Answer:It’s A 0,0

Step-by-step explanation:

lorasvet [3.4K]2 years ago

5 0

The x-intercept is defined to be the value of x when y is zero. Based on the graph of the function: f(x) = (x-4)(x+4), the x-intercepts are located at (-4, 0) and (4,0). At these points the graph intersects the x-axis. The midpoint of the x-intercepts is located at the middle of the two points. In this case, the graph shows that it is at the origin or at (0,0).

You might be interested in

Factor 2x² + 13x + 20

emmasim [6.3K]

Answer:

(2x+5)(x+4)

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Can someone help me with this math homework please!

blondinia [14]

Answer:

Step-by-step explanation:

y coordinates must be at the numerator, while x coordinates at the denominator

4 0

3 years ago

7/7q+21= x /5q^2-45 then x=?

anzhelika [568]

Answer:

x = 5q - 15

Step-by-step explanation:

$\frac{7}{7q+21}=\frac{x}{5q^{2}-45}\\\\\frac{7}{7(q+3)}=\frac{x}{5 (q^{2} -9)}\\\\frac{1}{q+3}=\frac{x}{5*(q^{2}-3^{2})}\\\\\frac{1}{q+3}=\frac{x}{5(q+3)(q-3)}\\\\\frac{1}{q+3}*5*(q+3)(q-3)=x\\\\5(q-3)=x\\\\x= 5q-15$