PQRS is a parallelogram Given
SR=PQ property of parallelogram
m∠S=m∠Q property of parallelogram
SP=QR property of parallelogram
XP=RY given
SP-XP=QR-RY substitution
SX=QY segment subtraction
ΔSRX is conggruent to ΔQPY SAS theorem (side-angle-side)
XR=YP CPCTC (corresponding parts of congruent triangles are congruent)
Answer:
The median, because the data distribution is skewed to the right
Step-by-step explanation:
If the longer part of the box is to the right (or above) the median, the data is said to be skewed right. If the longer part is to the left (or below) the median, the data is skewed left. The data is skewed right. The median would be a better estimate, because one or two numbers on the high end will cause the numbers to be skewed to the right, and the mean to be high
Answer:
W - (-4,4)
X - (-1,4)
Y - (-1,2)
Z - (-4,2)
Step-by-step explanation:
hope it helps. :)
If we draw a diagonal which will also be a transversal DB, then we get ∠ADB is congruent to ∠CBD by Alternate interior angles.
It will be the first option.
Answer:
3/14
Step-by-step explanation:
1st subtract the y's
the subtract the x's in the same order
-9 - 5 = -14
put the first result over the second
-3/-14 = 3/14
