V=(1/3)hpir^2
lets say this is original, undoubled volume
so o=v=(1/3)hpir^2
so for new volume, or n, that is r to 2r, doubled radius
n=(1/3)hpi(2r)^2
n=(1/3)hpi4r^2
n=4((1/3)hpir^2)
remmember that o=(1/3)hpir^2
n=4(o)
it is 4 times the old one
= 5x + 35 = -3
- 35 = -35
5x = -38
/ 5 = / 5
x = -7.6
Answer:
[?] = 4
(the complete term is 
)
Step-by-step explanation:
272155
I hope I helped, good luck
