So we can start with the full of possibilities and eliminate them one by one.
The full set is {0,1,2,3,4,5,6,7,8,9}.
Now we know that any prime greater than 2 is odd as otherwise it would have 2 as a factor, so we can eliminate all of these digits that would be an even number, leaving:
{1,3,5,7,9}
We also know that any prime greater than 5 cannot be a multiple of 5 and that all numbers with 5 in the digits are a multiple of 5, so we can eliminate 5.
{1,3,7,9}
We know that 11,13,17 and 19 are all primes, so we cannot eliminate any more of these, leaving the set:
{1,3,7,9} as our answer.
Answer:
h(k+6) if h(x)=15x+6
h(k+6)=15(k+6)+6=15k+90+6=15k+96
and h(x)= 2x-8
g o h is a composition function
First we find g o h
g o h is g(h(x))
We plug in h(x) in g(x)
We replace x with 2x-8 in g(x)


To find domain we look at the domain of h(x) first
Domain of h(x) is set of all real numbers
now we look at the domain of g(h(x))
Negative number inside the square root is imaginary. so we ignore negative number inside the square root
So to find domain we set 2x - 12 >=0 and solve for x
2x - 12 >=0
add both sides by 12
2x >= 12
divide both sides by 2
x > = 6