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Ulleksa [173]
3 years ago
13

What is the answer to y=(2x+5)(x-2) in standard form

Mathematics
1 answer:
docker41 [41]3 years ago
5 0

Answer:

i think it is Rewrite in Standard Form y=2x+5. y=2x+5 y = 2 x + 5.

Step-by-step explanation:

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Y=-.5x+15 plug in 8 for x and you get 11
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Gloria rides a bike 8 miles in 40 minutes.Nanette rides a bike 5 miles in 30 minutes.Who biked the farthest.
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Gloria biked the farthest.
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The volume of a cube with side length x is V(x)=x^3. The volume of a cylinder with radius x and height 0.5x is shown in the grap
abruzzese [7]

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  the cylinder volume is greater

Step-by-step explanation:

The volume of a cube with x=1 is ...

  V(1) = 1^3 = 1

The graph shows y ≈ 1.5 for x=1. Since 1.5 > 1, the volume of the cylinder is greater.

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3 years ago
Calculate the mean, median, mode, range, and 5 Number Summary of the following data set: 5,6,8,4,7,5,4,2,5,6,5,2,1,4
Artist 52 [7]

Answer:

mean = 4.57, median = 5 , mode = 5, range =7 ,

five number summary: Minimum value= 1 , First Quartile = 4, Median = 5

Third Quartile  = 6, Maximum value = 8

Step-by-step explanation:

First arrange the data in ascending order.

1,2,2,4,4,4,5,5,5,5,6,6,7,8

Mean = sum of all numbers / total numbers

         = 1+2+2+4+4+4+5+5+5+5+6+6+7+8 / 14

         = 64 / 14

         = 4.57

Median:

Since the given data is even number so, we can find median by taking mean of 2 middle numbers.

so the middle numbers are 7th and 8th  data i.e, 5 and 5

Median =(5+5)/2

           = 5

Mode:

The most repetitive number in the data set is mode

So Mode = 5

Range:

Range can be found by subtracting smallest number from largest number in the data set.

Smallest number  = 1, Largest number = 8

Range= Largest number - Smallest number

        = 8-1 = 7

Five no Summary

Minimum value= 1

First Quartile ( 25 % mark )= 4

Median = 5

Third Quartile (75 % mark) = 6

Maximum value = 8

First quartile can be found by : consider the data on left of the median and find median among them

Third quartile can be found by:  consider the data on right of the median and find median among them

7 0
3 years ago
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