Question

Solve the following system of equations. Express your answer as an ordered pair in the format (a,b), with no spaces between the numbers or symbols.
3x+4y=16
-4x-3y=-19

Answer 1

Answer: (4,1)

Step-by-step explanation:

The given system of equations :

$3x+4y=16.............................(1)\\\\-4x-3y=-19...........................(2)$

Multiplying equation (1) by 4 and equation (2) by 3 we get,

$12x+16y=64.............................(3)\\\\-12x-9y=-57...........................(4)$

Add (3) and (4), we get

$7y=7\\\\\Rightarrow\ y=1$

Substitute y=1 in (1), we get

$3x+4(1)=16\\\\\Rightarrow\ 3x=12\\\\\Rightarrow x=4$

Hence, the solution of the given system = (4,1)

Answer 2

Solve it by substitution. First let's rewrite the first equation (3x+4y=16) so we have y = something, then we'll substitue that in to the other equation.
3x+4y=16
4y=-3x+16
y=-3/4x+4

Now we can substitute this into the other equation.