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Anvisha [2.4K]
3 years ago
6

Solve the following system of equations. Express your answer as an ordered pair in the format (a,b), with no spaces between the

numbers or symbols.
3x+4y=16
-4x-3y=-19
Mathematics
2 answers:
malfutka [58]3 years ago
7 0

Answer: (4,1)

Step-by-step explanation:

The given system of equations :

3x+4y=16.............................(1)\\\\-4x-3y=-19...........................(2)

Multiplying equation (1) by 4 and equation (2) by 3 we get,

12x+16y=64.............................(3)\\\\-12x-9y=-57...........................(4)

Add (3) and (4), we get

7y=7\\\\\Rightarrow\ y=1

Substitute y=1 in (1), we get

3x+4(1)=16\\\\\Rightarrow\ 3x=12\\\\\Rightarrow x=4

Hence, the solution of the given system = (4,1)

Contact [7]3 years ago
4 0
Solve it by substitution. First let's rewrite the first equation (3x+4y=16) so we have y = something, then we'll substitue that in to the other equation.
3x+4y=16
4y=-3x+16
y=-3/4x+4

Now we can substitute this into the other equation.
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Step-by-step explanation:

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(x+2)(x+2)+(x)(x)=394\\ \\x^2+2x+2x+4+x^2=394\\ \\2x^2+4x+4-394=0\\ \\2x^2+4x-390=0\\ \\x^2+2x-195=0\\ \\D=2^2-4\cdot (-195)=4+780=784\\ \\\sqrt{D}=28\\ \\x_{1,2}=\dfrac{-2\pm 28}{2\cdot 1}=-15,\ 13

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