We know that
<span>ρ = density of gasoline = 737 kg/m³ (at T = 60°F = 15.6°C)
</span>ρ = m/V
ρV = m
V = m/ρ
V = 49.0 kg / 737 kg/m³
<span>V = 0.066 m³
[volume of the tank]=L*W*H-----> H=volume/[L*W]----> H=0.066/(0.9*0.4)
H=0.1833 m
the answer is
t</span><span>he depth of the tank is 0.18 m</span>
Answer:
18.18 mph
Step-by-step explanation:
Is that all the question says can you give it into more details
So I can help you out
5y-5y^2-5+2+2y+3y^2-1
collect like terms
7y-2y^2-4
reorder the terms
-2y^2+7y-4
-2y^2+7y-4 is your final answer, I hope this helps!