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Leni [432]
3 years ago
11

Please help me!! I don’t understand!!!

Mathematics
1 answer:
Dovator [93]3 years ago
7 0

Answer:

Ask your John Brown teacher!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Step-by-step explanation:

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Evaluate the function f(-2) - h(4) given the following functions: f(x) = 4x​ 2​+ 9 h(x) = 3x - 14
Goryan [66]

Answer:

-86

Step-by-step explanation:

simplify each equation as much as possible

f(x)= 4x(2+9) add

4x(11) multiply

f(x)=44x

substitute given numbers into each equation

44(-2)=-88                3(4)-14= 12-14=-2

combine equations

-88-(-2)= -86   add since you are subtracting a negative number

4 0
3 years ago
What is 2x + 5 (y-1) when x=8 and y=5
Neko [114]

Step-by-step explanation:

2x + 5 (y-1)

16+20

=36

hope it helps you

8 0
2 years ago
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Are the two triangles congruent ? Please answer correctly !!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!
mel-nik [20]

Answer:

yes

Step-by-step explanation:

4 0
3 years ago
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What is your number?
Goryan [66]

Answer:

13 and 11

Step-by-step explanation:

how is helpful

5 0
3 years ago
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Solve the following system
scZoUnD [109]

Answer:

{x = -4 , y = 2 ,  z = 1

Step-by-step explanation:

Solve the following system:

{-2 x + y + 2 z = 12 | (equation 1)

2 x - 4 y + z = -15 | (equation 2)

y + 4 z = 6 | (equation 3)

Add equation 1 to equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - 3 y + 3 z = -3 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Divide equation 2 by 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Add equation 2 to equation 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+5 z = 5 | (equation 3)

Divide equation 3 by 5:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 3 from equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y+0 z = -2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{-(2 x) + 0 y+2 z = 10 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 2 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = 8 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = -4 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer:  {x = -4 , y = 2 ,  z = 1

4 0
3 years ago
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