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Rina8888 [55]
3 years ago
13

El equipo de béisbol de los Gatos Salvajes de Ludlow, un equipo de las ligas menores de la organización de los Indios de Clevela

nd, juega 70% de sus partidos por la noche y 30% de día. El equipo gana 50% de los juegos nocturnos y 90% de los diurnos. De acuerdo con el periódico de hoy, ganaron el día de ayer. ¿Cuál es la probabilidad de que el partido se haya jugado de noche?
Mathematics
1 answer:
mario62 [17]3 years ago
7 0

Answer:

0.5645

Step-by-step explanation:

De la pregunta anterior, se nos dan los siguientes valores para el equipo de Ludlow

Probabilidad de jugar de noche = 70% = 0.7

Probabilidad de ganar en la noche = 50% = 0.5

Probabilidad de jugar durante el día = 30% = 0.3

Probabilidad de ganar durante el día = 90% = 0.9

Probabilidad de que cuando ganaron ayer, el juego se jugó por la noche =

(Probabilidad de jugar de noche × Probabilidad de ganar de noche) ÷ [(Probabilidad de jugar de noche × Probabilidad de ganar de noche) + (Probabilidad de jugar de día × Probabilidad de ganar de día)]

Probabilidad de que cuando ganaron ayer, el juego se jugó de noche = (0.5 × 0.7) ÷ (0.5 × 0.7) + (0.9 × 0.3)

= 0.35 ÷ 0.35 + 0.27

= 0.35 ÷ 0.62

= 0.5645

La probabilidad de que el partido se haya jugado de noche = 0.5645

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Amy and rob each improve thier yards by pmanting rose bushes and ivy. They brought thier supplies from the same store. Amy spent
Rzqust [24]

Answer: cost of 1 pot of ivy = $12

Cost of 1 rose bush =$ 10

Step-by-step explanation:

Step 1

Let rose bushes be represented as r

and pot of ivy be represented as p

such that Amy who spent 82 dollars on 7 rose bushes and 1 pot of ivy can be expressed as

7 r + p = 82----- eqn 1

Rob who spent 74 on 5 rose bushes and 2 pots of ivy can  be expressed as

5r +2 p = 74----- eqn 2

Step 2

Solving

7 r + p = 82----- eqn 1

5r +2 p = 74----- eqn 2

By elimination method Multiply eqn 1 by 5 and eqn 2 by 7

35r+ 5p= 410--- eqn 3

35r+ 14p =518--- eqn 4

Subtracting eqn 4 from eqn 3

9p = 108

p = 108/9

p=12

p = pot of ivy = $12

therefore rose bush  wll be ( from equation 1)

7r+ p= 82

7r=82-12

7r= 70 r= 70/7

r= rose bush =$ 10

5 0
2 years ago
Bryce grows a sunflower that contains 1,354 sunflower seeds. Six people share the harvested seeds. If they share the seeds equal
iragen [17]

Answer: 4 seeds will left over.

Step-by-step explanation:

Total sunflower seeds = 1354

Number of people shared sunflower  seeds equally = 6

By division operation,

Number of seeds each people will get = (Total sunflower  seeds) ÷ (Number of people shared seeds equally)

= (1354) \div (6)

=225\dfrac{4}{6}

Hence, each people will get 256 sunflower seeds and 4 seeds will left.

5 0
2 years ago
Jayden has been reading a 275275275-page book for English class. On average, he has read about 101010 pages in 151515 minutes (\
maxonik [38]
First let's define variables:
 r: reading
 s: skimming
 We write the system of equations that adapts to the problem:
 r + s = 275
 (15/10) r + (10/15) s = 355
 We solve the system of equations:
 r = 206
 s = 69
 Note: see attached image for system solution.
 Answer: 
 Jayden had to skim 69 pages through

8 0
2 years ago
9. Choose whether the number is rational or irrational
lutik1710 [3]
The square root of 169=13 so it is rational
4 0
2 years ago
The test to detect the presence of respiratory syncytial virus is 97% accurate for a person who has the virus and 99% accurate f
Setler79 [48]

Answer:

The probability that a randomly selected person gets incorrect result is 2.2 × 10⁻⁴

Step-by-step explanation:

The parameters given are;

The accuracy of the test for a person who has the respiratory synctial virus = 97%

The accuracy of the test for a person who does not have the respiratory synctial virus = 99%

We have;

a = TP =

b = FP

c = FN

d = TN

a/(a + c) = 0.97

d/(d + b) = 0.99

a/(a + b) = 0.97*0.0055/(0.97*0.0055 + (1 - 0.99)*(1-0.0055))

PPV = 0.349 = 34.9%

Therefore, we have;

a/(a + c) = 0.97 and

a/(a + b)  =  0.349

0.97(a + c) =0.349(a + b)

(0.97 - 0.349)a = 0.349·b - 0.97·c

a = (0.349·b - 0.97·c)0.621

b × (1 - 0.0055) = (1 - 0.97)×(1 - 0.0055)

b = 1 - 0.97 = 0.03

Similarly,

c = 1 - 0.99 = 0.01

The proportion of the population that have false positive and false negative = 0.03 + 0.01 = 0.04 = 4%

The probability that a randomly selected person gets incorrect result = 0.04×0.0055 = 0.00022.

5 0
2 years ago
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