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kirill115 [55]
3 years ago
13

Help me answer please

Mathematics
1 answer:
fiasKO [112]3 years ago
6 0

Answer:

25

Step-by-step explanation:

b=4x+1    h=x+1     A=175

A=bh

Substitute: 175=(4x+1)(x+1)

Expand: 175=4x^2+5x+1

Subtract 175

4x^2+5x-174=0

Solve w/quadratic formula

(-5 <u>+</u> sqrt(25+2784))/8

Simplify: x=6 or -29/4

Distance is positive, so x=6

4x+1=4*6+1=25


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Zeke had 9 dvds. His mother bought d more DVD. Write an expression that shows how many dvds zeke has now
Kitty [74]

Answer: 9+d=x or x=9+d

d-the new dvds

x-the unknown total

9-the dvds Zeke owned before

6 0
3 years ago
The square below has a side length of 5 cm. What is the length of the missing side? Round your answer to the nearest whole numbe
Misha Larkins [42]

Answer:

D. about 7 cm

Step-by-step explanation:

You can use the pythagorean theorem.

You have a triangle with sides of 5 and 5, so that means the third side is:

a^2 + b^2 = c^2 --> 5^2 + 5^2 = c^2\\25 + 25 = c^2\\50 = c^2\\c = 5\sqrt{2}

rounding:

5\sqrt{2} = 7

5 0
3 years ago
Read 2 more answers
In an experiment, college students were given either four quarters or a $1 bill and they could either keep the money or spend it
gavmur [86]

Answer:

a) P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b) P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c)  A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

Step-by-step explanation:

Assuming the following table:

                                                     Purchased Gum      Kept the Money   Total

Students Given 4 Quarters              25                              14                      39

Students Given $1 Bill                       15                               29                    44

Total                                                   40                              43                     83

a. find the probability of randomly selecting a student who spent the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student spent the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{40}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{15}{83}

And if we replace we got:

P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b. find the probability of randomly selecting a student who kept the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student kept the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{43}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{29}{83}

And if we replace we got:

P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c. what do the preceding results suggest?

For this case the best solution is:

A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

3 0
3 years ago
Find the GCF. 12, 18, and 84
Dmitry [639]

Answer: 6

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
I need Help please!!
PSYCHO15rus [73]
I think it’s A because the s is between P&Q and S&C if it’s wrong I’m sorry!
3 0
3 years ago
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