This is a systems of equations problem. To begin, we need to set up our equations.
If there was a total of 548 dollars collected, and adult tickets cost $6, and students tickets $4, this equation represents that situation.
6a + 4s = 548
The variable a stands for adult, and variable s for student. Now, if 12 more student tickets were sold than adults, this would represent that.
a + 12 = s
Now we can set it up as a systems of equations.
![\left \{ {{6a + 4s = 548} \atop {a + 12 = s}} \right.](https://tex.z-dn.net/?f=%20%5Cleft%20%5C%7B%20%7B%7B6a%20%2B%204s%20%3D%20548%7D%20%5Catop%20%7Ba%20%2B%2012%20%3D%20s%7D%7D%20%5Cright.%20%20)
Because s = a + 12, we can plug that in into the other equation.
6a + 4(a + 12) = 548
Distribute 4.
6a + 4a + 48 = 548
Combine like terms.
10a + 48 = 548
Subtract 48 from both sides.
10a = 500
Divide both sides by 10.
a = 50
Plug a into the original equation.
50 + 12 = s
Combine like terms.
62 = s
<h3>There were 62 student tickets and 50 adult tickets sold.</h3>
I think she put 32 books in each pile because 229/7=32.7 but if I was asked to round it it would be 33.
There are four sides
6.5 x 4 = 26
The graph should look like the below image
It’s a straight line that passes through the origin.