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PIT_PIT [208]
3 years ago
5

Player B’s longest home run distance is 500 ft. There are 5280 ft in 1 mi. How many home runs would Player B need to hit at his

longest distance for the total to be greater?
Mathematics
1 answer:
Flura [38]3 years ago
3 0
5280 ÷ 500 = (number of home runs needed to reach a mile distance)

5280 ÷ 500 = 10.56

cant hit part of a home run so round up to 11.
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The circumference of a circle can be found using the formula C = 2r. Which is an equivalent equation solved for r? r = C r = C(2
vaieri [72.5K]

Answer:

r equals StartFraction C Over 2 pi EndFraction

Step-by-step explanation:

we know that

The circumference of a circle is equal to

C=2\pi r

where

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Solve for r

That means -----> isolate the variable r

Divide by 2π both sides

\frac{C}{2\pi}=\frac{2\pi r}{2\pi}

Simplify right side

\frac{C}{2\pi}=r

Rewrite

r=\frac{C}{2\pi}

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5 0
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maksim [4K]

Answer:

Option D.

Step-by-step explanation:

Minimize the objective function P = 5x + 8y for the given constraints.

x\geq 0,y\geq 0

2x+3y\geq 15

3x+2y\geq 15

The related equations of above inequalities are

2x+3y=15

3x+2y=15

For 2x+3y=15,

x     y

0     5

7.5   0  

Plot (0,5) and (7.5,0) and join them by straight line.

For 3x+2y=15,

x     y

0     7.5

5      0  

Plot (0,7.5) and (5,0) and join them by straight line.

Check the inequalities for (0,0).

2(0)+3(0)\geq 15\Rightarrow 0\geq 15 False

3(0)+2(0)\geq 15\Rightarrow 0\geq 15 False

It means both lines are solid lines and shaded region for each lies opposite side of (0,0).

From the below graph it is clear that the vertices of feasible region are (0,7.5), (3,3), (7.5,0).

Point       P = 5x + 8y

(0,7.5)     P=5(0)+8(7.5)=60

(3,3)     P=5(3)+8(3)=15+24=39

(7.5,0)     P=5(7.5)+8(0)=37.5 (Minimum)

So, minimum value is 37.5.

Therefore, the correct option is D.

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