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PIT_PIT [208]
3 years ago
5

Player B’s longest home run distance is 500 ft. There are 5280 ft in 1 mi. How many home runs would Player B need to hit at his

longest distance for the total to be greater?
Mathematics
1 answer:
Flura [38]3 years ago
3 0
5280 ÷ 500 = (number of home runs needed to reach a mile distance)

5280 ÷ 500 = 10.56

cant hit part of a home run so round up to 11.
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Fynjy0 [20]

Answer:

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Step-by-step explanation:

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5 0
2 years ago
Jana ran the first 3 and a half miles of a 5 mile race in 1 3rd of an hour. what was her average rate, in mph, for the first par
Lisa [10]

Answer:

always try to draw a diagram first

Step-by-step explanation:

Jana ran The first 3.5 miles in 1/3 of an hour. remember the problem tells us that we want our answer in miles per hour or mph. so we have to set up our problem so that our units match in the end. The diagram above shows 3.5 mi over 1/3 hour. so we must divide 3.5 miles by 1/3 hour

note:

3 \frac{1}{2} mi =  \frac{7mi}{2}

therefore

\frac{7mi}{2}  \:  \div  \:  \frac{1hr}{3}  =

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7 0
2 years ago
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Alinara [238K]

Answer:

286 degrees

Step-by-step explanation:

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g100num [7]
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