Player B’s longest home run distance is 500 ft. There are 5280 ft in 1 mi. How many home runs would Player B need to hit at his
longest distance for the total to be greater?
1 answer:
5280 ÷ 500 = (number of home runs needed to reach a mile distance)
5280 ÷ 500 = 10.56
cant hit part of a home run so round up to 11.
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the total area for both floors is 1800 square feet
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360 per hour, pretty sure this is correct !
Theos number is -2/5
4x + 20 = 10
-20 -20
4x = -10
x = -4/10
x = -2/5
