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Murrr4er [49]
3 years ago
5

The company had 1,600 shares of 3.0%, $100 par value preferred stock outstanding that paid a cumulative dividend. The amount of

dividends received by the common shareholders during Year 3 would be:
Business
2 answers:
daser333 [38]3 years ago
4 0

Answer:

C. $2600

Explanation:

First, the complete question is as follows:

Curtain Co. paid dividends of $4,000; $5,000; and $8,000 during Year 1, Year 2, and Year 3, respectively. The company had 1,600 shares of 3.0%, $100 par value preferred stock outstanding that paid a cumulative dividend. The amount of dividends received by the common shareholders during Year 3 would be:

A. $4800

B. $1000

C. $2600

D. $800

Solution

First, what is the yearly dividend for the preferred stock

= (The Number of shares x Par value) x 3%

= (1600 shares x $100) x 0.03

= $4,800

Use this value to determine the schedule of Preferrence dividend  as follows:

Year 1: Preferred dividend = $4,000,

Preferred dividend in arrears for year 1 = Yearly dividend - paid dividend in year 1

= $4,800 - $4,000 = $800

Year 2: Preferred dividend = $5000

Preferred dividend in arrears for year 2= $4,400 + $800 -$5,000 = $600

year 3: Preferred Dividend = Yearly dividend + dividend in arrears from year 2

= $600 + $4,800 = $5,400

Therefore, the dividends available to common stockholders = $8,000- $5,400 = $2,600

noname [10]3 years ago
4 0

The question is incomplete! The complete question along with answer and explanation is provided below.

Question:

Curtain Co. paid dividends of $4,000; $5,000; and $8,000 during Year 1, Year 2, and Year 3 respectively. The company had 1,600 shares of 3.0%, $100 par value preferred stock outstanding that paid a cumulative dividend. The amount of dividends received by the common shareholders during Year 3 would be:

A. $4800

B. $1000

C. $2600

D. $800

Answer:

C. $2600

Explanation:

Paid dividend in year 1: $4,000

Paid dividend in year 2: $5,000

Paid dividend in year 3: $8,000

First we have to calculate the annual preferred dividend.

Annual preferred dividend = $100*1,600*0.03

Annual preferred dividend = $4,800

Year 1:

dividends in arrears = preferred dividend - paid dividend

dividends in arrears = $4,800 - $4,000

dividends in arrears = $800

Year 2:

dividends in arrears = previous arrears + preferred dividend - paid dividend

dividends in arrears = $800 + $4,800 - $5,000

dividends in arrears = $600

Year 3:

dividends in arrears =  $600 + $4,800  = $5,400.

paid dividend - dividends in arrears = $8000 - $5,400 = $2,600

Hence, common shareholders received $2,600

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Suppose that output (Y ) in an economy is given by the following aggregate production function: Yt = Kt + Nt where Kt is capital
shusha [124]

Answer:

Check the explanation

Explanation:

Yt = Kt + Nt

Taking output per worker, we divide by Nt

Yt/Nt = Kt/Nt + 1

yt = kt + 1

where yt is output per worker and kt is capital per worker.

a) With population being constant, savings rate s and depreciation rate δ.

ΔKt = It - δKt

dividing by Nt, we get

ΔKt/Nt = It/Nt - δKt/Nt ..... [1]

for kt = Kt/Nt, taking derivative

d(kt)/dt = d(Kt/Nt)/dt ... since Nt is a constant, we have

d(kt)/dt = d(Kt/Nt)/dt = (dKt/dt)/Nt = ΔKt/Nt = It/Nt - δKt/Nt = it - δkt

thus, Capital accumulation Δkt = i – δkt

In steady state, Δkt = 0

That is I – δkt = 0

S = I means that I = s.yt

Thus, s.yt – δkt = 0

Then kt* = s/δ(yt) = s(kt+1)/(δ )

kt*= skt/(δ) + s/(δ)

kt* - skt*/(δ) = s/(δ)

kt*(1- s/(δ) = s/(δ)

kt*((δ - s)/(δ) = s/(δ)

kt*(δ-s)) = s

kt* = s/(δ -s)

capital per worker is given by kt*

b) with population growth rate of n,

d(kt)/dt = d(Kt/Nt)/dt =

= \frac{\frac{dKt}{dt}Nt - \frac{dNt}{dt}Kt}{N^{2}t}

= \frac{dKt/dt}{Nt} - \frac{dNt/dt}{Nt}.\frac{Kt}{Nt}

= ΔKt/Nt - n.kt

because (dNt/dt)/Nt = growth rate of population = n and Kt/Nt = kt (capital per worker)

so, d(kt)/dt = ΔKt/Nt - n.kt

Δkt = ΔKt/Nt - n.kt = It/Nt - δKt/Nt - n.kt ......(from [1])

Δkt = it - δkt - n.kt

at steady state Δkt = it - δkt - n.kt = 0

s.yt - (δ + n)kt = 0........... since it = s.yt

kt* = s.yt/(δ + n) =s(kt+1)/(δ + n)

kt*= skt/(δ + n) + s/(δ + n)

kt* - skt*/(δ + n) = s/(δ + n)

kt*(1- s/(δ + n)) = s/(δ + n)

kt*((δ + n - s)/(δ + n)) = s/(δ + n)

kt*(δ + n -s)) = s

kt* = s/(δ + n -s)

.... is the steady state level of capital per worker with population growth rate of n.

3. a) capital per worker. in steady state Δkt = 0 therefore, growth rate of kt is zero

b) output per worker, yt = kt + 1

g(yt) = g(kt) = 0

since capital per worker is not growing, output per worker also does not grow.

c)capital.

kt* = s/(δ + n -s)

Kt*/Nt = s/(δ + n -s)

Kt* = sNt/(δ + n -s)

taking derivative with respect to t.

d(Kt*)/dt = s/(δ + n -s). dNt/dt

(dNt/dt)/N =n (population growth rate)

so dNt/dt = n.Nt

d(Kt*)/dt = s/(δ + n -s).n.Nt

dividing by Kt*

(d(Kt*)/dt)/Kt* = s/(δ + n -s).n.Nt/Kt* = sn/(δ + n -s). (Nt/Kt)

\frac{sn}{\delta +n-s}.\frac{Nt}{Kt}

using K/N = k

\frac{s}{\delta +n-s}.\frac{n}{kt}

plugging the value of kt*

\frac{sn}{\delta +n-s}.\frac{(\delta + n -s)}{s}

n

thus, Capital K grows at rate n

d) Yt = Kt + Nt

dYt/dt = dKt/dt + dNt/dt = s/(δ + n -s).n.Nt + n.Nt

using d(Kt*)/dt = s/(δ + n -s).n.Nt from previous part and that (dNt/dt)/N =n

dYt/dt = n.Nt(s/(δ + n -s) + 1) = n.Nt(s+ δ + n -s)/(δ + n -s) = n.Nt((δ + n)/(δ + n -s)

dYt/dt = n.Nt((δ + n)/(δ + n -s)

dividing by Yt

g(Yt) = n.(δ + n)/(δ + n -s).Nt/Yt

since Yt/Nt = yt

g(Yt) = n.(δ + n)/(δ + n -s) (1/yt)

at kt* = s/(δ + n -s), yt* = kt* + 1

so yt* = s/(δ + n -s) + 1 = (s + δ + n -s)/(δ + n -s) = (δ + n)/(δ + n -s)

thus, g(Yt) = n.(δ + n)/(δ + n -s) (1/yt) =  n.(δ + n)/(δ + n -s) ((δ + n -s)/(δ + n)) = n

therefore, in steady state Yt grows at rate n.

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3 years ago
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Nowadays, many of the huge factories and industries ___________to function if there was no adequate electric power. A. Were unab
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Option B. Nowadays, many of the huge factories and industries <u>Would be unable</u> to function if there was no adequate electric power.

<h3>What is electric power?</h3>

The rate of electrical energy transmission over an electric circuit per unit of time is measured as electric power in physics. P stands for power, which is denoted and measured using the SI unit of power, the watt, or one joule per second. Electric batteries and electric generators are frequently used to produce and supply electricity.

The speed at which energy is converted into an electrical circuit or used to produce work is known as electric power. It is a way to quantify how much energy is consumed over a certain period of time.

Read more on  electricity here: brainly.com/question/24786034

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The market for used cell phones is very popular in Barylia. However, several phones available in this market are of inferior qua
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SWOT analysis is a method of determining external strengths and weaknesses and internal opportunities and threats. True False
Kamila [148]

Answer:

False

Explanation:

SWOT analysis is a method of determining external strengths and weaknesses and internal opportunities and threats is a FALSE statement. SWOT analysis means

Strength

Weakness

Opportunities

Threat

Strength and weaknesses are the internal factors not external ones, strength and weakness comes from inside of the organisation. Any organisation capability to serve the customers well, having red hot selling products, creative employees can be its strength. If these elements are not performing well, they can become the weakness as well, therefore, SW is related with the internal environment of the organisation.

In the same way, opportunities and threats are posed by the outside environment, they are not internal elements and factors. Political, social, technological and legal environment can create both treat as well new and exciting opportunities for the organization.

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