Question

Write the equation of the line that passes through the point (-5,5) and has a slope of -8/5

Answer 1

Answer:

Therefore, the equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

                                             $y=\frac{-8}{5}x-3$  

Step-by-step explanation:

Given the point (-5, 5)

slope = m = -8/5

Using the slope intercept form:  

$y=mx+b$

Plugging point (-5, 5) and slope = m = -8/5 in the slope intercept form to find the y-intercept 'b'.

$5=\frac{-8}{5}\left(-5\right)+b$

$\mathrm{Switch\:sides}$

$\frac{-8}{5}\left(-5\right)+b=5$

$8+b=5$

$8+b-8=5-8$

$b=-3$

so the equation of the line will be:

$y=mx+b$

plugging m = -8/5 and b = -3 in slope intercept form

$y=\frac{-8}{5}x-3$      

Therefore, the equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

                                             $y=\frac{-8}{5}x-3$