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777dan777 [17]
3 years ago
14

Write the equation of the line that passes through the point (-5,5) and has a slope of -8/5

Mathematics
1 answer:
adoni [48]3 years ago
4 0

Answer:

Therefore, the equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

                                             y=\frac{-8}{5}x-3  

Step-by-step explanation:

Given the point (-5, 5)

slope = m = -8/5

Using the slope intercept form:  

y=mx+b

Plugging point (-5, 5) and slope = m = -8/5 in the slope intercept form to find the y-intercept 'b'.

5=\frac{-8}{5}\left(-5\right)+b

\mathrm{Switch\:sides}

\frac{-8}{5}\left(-5\right)+b=5

8+b=5

8+b-8=5-8

b=-3

so the equation of the line will be:

y=mx+b

plugging m = -8/5 and b = -3 in slope intercept form

y=\frac{-8}{5}x-3      

Therefore, the equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

                                             y=\frac{-8}{5}x-3  

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