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g100num [7]
3 years ago
15

Which equation represents the graph?

Mathematics
1 answer:
klio [65]3 years ago
6 0
The second option.

That is because
y -3 = - \frac{1}{2}(x + 1) \\ (y -3)+3 = (- \frac{1}{2} x - \frac{1}{2}) + 3 \\ y = - \frac{1}{2}x + 2 \frac{1}{2}
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Which process will create a figure that is congruent to the figure shown?<br><br> A , B , C or D ?
Darya [45]
I believe the answer would be B
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If you have 24 dozen Shamrock cookies horseshoe cookies mint cupcakes and you sold four times as many cupcakes as cookies and th
Elden [556K]

Answer:

144

Step-by-step explanation:

108 plus 36 then you will get 144

3 0
3 years ago
Neeed Helppp plzzz ! True or False ?!!
Mamont248 [21]

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5 0
2 years ago
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An object moves in simple harmonic motion with period 8 seconds and amplitude 6 cm. At time t = 0 seconds, its displacement d fr
Vladimir79 [104]

In the equation model, the simple harmonic motion is d=6sin(πt/4)-6 if the object moves in simple harmonic motion with a period of 8 seconds and amplitude of 6 cm.

<h3>What is simple harmonic motion?</h3>

Simple Harmonic Motion is described as a motion in which the restoring force is proportionate to the body's displacement from its mean position.

We have:

Amplitude A = 6 cm

Time period = 8 seconds

T = 2π/w

8 = 2π/w

w = π/4

Its displacement d from rest is -6 cm, and initially, it moves in a positive direction.

d(0) = -6 cm at t = 0

The equation becomes:

\rm d = 6sin(\dfrac{\pi}{4}t)-6

Thus, in the equation model, the simple harmonic motion is d=6sin(πt/4)-6 if the object moves in simple harmonic motion with a period of 8 seconds and amplitude of 6 cm.

Learn more about the simple harmonic motion here:

brainly.com/question/17315536

#SPJ1

4 0
2 years ago
Sin(a+b).cos(a-b) = sinacosa + sinbcosb
Rainbow [258]
Sin (A + B) = sin A cos B + cos A Sin B 
<span>Cos (A - B) = cos A cos B + sin A sin B </span>

<span>=> (SinACosB+ CosASinB) (CosACosB +SinASinB) </span>

<span>=>SinACosACos^2B+Sin^2ACosBSinB+Cos^2A... </span>

<span>=>SinACosA(Cos^2B+Sin^2B) +SinBCosB(Sin^2A+Cos^2A) </span>
<span>we know that Sin^2+Cos^2=1 </span>
<span>=>SinACosA(1)+SinBCosB(1) </span>
<span>=SinACosA+SinBCosB </span>
<span>Proved 

</span>
4 0
3 years ago
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