The x² term will be C(5,2)x²·2³ = 80x².
The coefficient is 80.
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C(n, k) = n!/(k!·(n-k)!)
C(5, 2) = 5·4/(2·1) = 10
Answer in fraction form: -17/4 < x < 11/4
Answer in decimal form: -4.25 < x < 2.75
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Work Shown:
|4x+3| - 9 < 5
|4x+3| < 5+9 .... adding 9 to both sides
|4x+3| < 14
-14 < 4x+3 < 14 .... see note at the bottom
-14-3 < 4x < 14-3 .... subtracting 3 from all sides
-17 < 4x < 11
-17/4 < x < 11/4 .... divide all sides by 4
-4.25 < x < 2.75
This says that x is between -4.25 and 2.75, but x is not equal to either endpoint.
Note: I used the rule that |x| < k becomes -k < x < k where k is a positive real number.
Answer is C
3.2 oz + 4.7oz = 7.9 oz * 4 = 31.6oz total
-7(k+9)=9(k-5)-14k
-7k-63=(9k-45)-14k
-7k-63=-5k-45
-7k=-5k+18
-2k=18
k=-9
2 1/24
Rewriting our equation with parts separated
2/3+1+3/8
Solving the fraction parts
2/3+3/8=?
Find the LCD of 2/3 and 3/8 and rewrite to solve with the equivalent fractions.
LCD = 24
16/24+9/24=25/24
Simplifying the fraction part, 25/24,
25/24=1 1/24
Combining the whole and fraction parts
1+1+1/24=2 1/24