All categories

3 years ago

How to solve 4+y=9.5

Mathematics

2 answers:

soldi70 [24.7K]3 years ago

8 0

Steps to solve:

4 + y = 9.5

~Subtract 4 to both sides

y = 5.5

Best of Luck!

Zigmanuir [339]3 years ago

4 0

Answer:

$\framebox{\parbox[t][1.0cm]{4.50cm}{\addvspace{0.2cm} \centering $ x \;=\; {5.5} $ } }\\$

Step-by-step explanation:

$4+y=9.5$

Let's simplify this equation.

To solve this equation, we must first subtract 4 from both sides of the equation.

$y+4-4=9.5-4$

Let's see what we got.

$y=5.5$

Now you got your answer!

Hope this helps!

You might be interested in

Please solve 21 points plsss help :()

asambeis [7]

Answer:

Answer = 61/157

Step-by-step explanation:

First add all the numbers together.

56 + 61 + 14 + 26 = 157

Then take the number of brown hair and blue eyed people (61) and make a fraction out of all.

61/157

You can not simplify it more than that

Hope this helps

7 0

3 years ago

Factor:<br> -2 +8=-20<br> THANKS IN ADVANCE!!!

Anettt [7]

Answer:

-2 +8=-20 False

Step-by-step explanation:

Simplify -2 +8 --> 6

6= -20 is False

^ ^

sides arent equal

4 0

2 years ago

5.2.14. For the negative binomial pdf p (k; p, r) = k+r−1 (1 − p)kpr, find the maximum likelihood k estimator for p if r is know

Volgvan

Answer:

$\hat p = \frac{r}{\bar x +r}$

Step-by-step explanation:

A negative binomial random variable "is the number X of repeated trials to produce r successes in a negative binomial experiment. The probability distribution of a negative binomial random variable is called a negative binomial distribution, this distribution is known as the Pascal distribution".

And the probability mass function is given by:

$P(X=x) = (x+r-1 C k)p^r (1-p)^{x}$

Where r represent the number successes after the k failures and p is the probability of a success on any given trial.

Solution to the problem

For this case the likehoof function is given by:

$L(\theta , x_i) = \prod_{i=1}^n f(\theta ,x_i)$

If we replace the mass function we got:

$L(p, x_i) = \prod_{i=1}^n (x_i +r-1 C k) p^r (1-p)^{x_i}$

When we take the derivate of the likehood function we got:

$l(p,x_i) = \sum_{i=1}^n [log (x_i +r-1 C k) + r log(p) + x_i log(1-p)]$

And in order to estimate the likehood estimator for p we need to take the derivate from the last expression and we got:

$\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\frac{x_i}{1-p}$

And we can separete the sum and we got:

$\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\sum_{i=1}^n \frac{x_i}{1-p}$

Now we need to find the critical point setting equal to zero this derivate and we got:

$\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\sum_{i=1}^n \frac{x_i}{1-p}=0$

$\sum_{i=1}^n \frac{r}{p} =\sum_{i=1}^n \frac{x_i}{1-p}$

For the left and right part of the expression we just have this using the properties for a sum and taking in count that p is a fixed value:

$\frac{nr}{p}= \frac{\sum_{i=1}^n x_i}{1-p}$

Now we need to solve the value of $\hat p$ from the last equation like this:

$nr(1-p) = p \sum_{i=1}^n x_i$

$nr -nrp =p \sum_{i=1}^n x_i$

$p \sum_{i=1}^n x_i +nrp = nr$

$p[\sum_{i=1}^n x_i +nr]= nr$

And if we solve for $\hat p$ we got:

$\hat p = \frac{nr}{\sum_{i=1}^n x_i +nr}$

And if we divide numerator and denominator by n we got:

$\hat p = \frac{r}{\bar x +r}$

Since $\bar x = \frac{\sum_{i=1}^n x_i}{n}$

4 0

3 years ago

HELP!!!!!!!!!!!!!!!!!!!!!!

Furkat [3]

Answer:

See below.

Step-by-step explanation:

Congruent sides:

SU and FO

UN and OG

SN and FG

Congruent angles:

<S and <F

<U and <O

<N and <G

6 0

2 years ago

Square root:27 + SR:48+SQ:12 = ???

Anika [276]

Sqrt(27)+sqrt(48)+sqrt(12)
Sqrt(27)=sqrt(3*3*3)=3*sqrt(3)
Sqrt(48)=sqrt(4*4*3)=4*sqrt(3)
Sqrt(12)=sqrt(2*2*3)=2*sqrt(3)
Add the three to get 9*sqrt(3)
Final answer:
9*sqrt(3)
Hope I helped :)

5 0

3 years ago

Read 2 more answers