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pantera1 [17]
3 years ago
14

What is the best representation of 1 and 3/4?

Mathematics
1 answer:
Rzqust [24]3 years ago
5 0

the best would be 1.75

Step-by-step explanation:

3/4 turned into a decimal is .75 then you would add the 1 making it 1.75.

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Sam takes 6 apples from the basket, that is, only 25% of all apples in the
Leya [2.2K]

Answer:

24 apples

Step-by-step explanation:

set up the problem 6=0.25X. then divide 6 by 0.25 to get X by itself. 24 is the answer.

6 0
2 years ago
Can someone please answer question number 7 with explanation ❤️
Ulleksa [173]

Answer:

a

Step-by-step explanation:

you have to find the hole volume of the other shapes.

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3 years ago
PLS PLS PLS I NEED HELP FAAAAAAAASSSSST GIVING BRAINLIEST TO QUICKEST CORRECT ​
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c hope this helps

Step-by-step explanation:

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2 years ago
Read 2 more answers
Is the following relation a function?<br><br><br> x y<br> 1 4<br> −1 −2<br> 3 10<br> 5 16
Sergio [31]
No , because it doesn’t have a pattern . For example put the numbers in a chart 1+3 = 4 , -1+3 =2 , 3+7=10 , 5+11=16 , there’s no pattern
3 0
3 years ago
Complete the given diagram by dragging expressions to each leg of the triangle. Then, correctly complete the equation to derive
Nimfa-mama [501]

The equation to derive the distance d is \sqrt{(x2-x1)^2+(y2-y1)^2}. The lengths of the other legs of the given triangle are (y2 - y1) and (x2 - x1).

<h3>What is the formula for calculating the distance between two points?</h3>

Consider the two points (x1, y1) and (x2, y2)

The formula used for calculating the distance between the two points is

distance = \sqrt{(x2-x1)^2+(y2-y1)^2}

<h3>Calculation:</h3>

Given that,

The triangle in the graph has vertices (x1, y1), (x2, y2), and (x2, y1)

Since this triangle makes 90°, it is a right-angled triangle.

Hypotenuse = (x1, y1) to (x2, y2), Adjacent = (x1, y1) to (x2,y1), and Opposite = (x2, y1) to (x2, y2).

Consider the length of the hypotenuse = d

So, using the distance formula, the length of the hypotenuse(d) is,

d = \sqrt{(x2-x1)^2+(y2-y1)^2}

And the lengths of the other two legs of the given triangle are,

Length of the adjacent side: (x1, y1) to (x2,y1)

= \sqrt{(x2-x1)^2+(y1-y1)^2}

= \sqrt{(x2-x1)^2+0}

= (x2-x1)

Length of the opposite side: (x2, y1) to (x2, y2)

= \sqrt{(x2-x2)^2+(y2-y1)^2}

= \sqrt{0+(y2-y1)^2}

= (y2-y1)

Therefore, the derived distances for the given triangle are:

d=\sqrt{(x2-x1)^2+(y2-y1)^2}, (x2 - x1), and (y2 - y1).

Learn more about the distance between two points here:

brainly.com/question/661229

#SPJ1

4 0
2 years ago
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