Factorizing the denominator gives

Then the partial fraction decomposition would take the form

First add the numbers together:
-13+(-5),6,(-7),9=-10
Then divide that number by the total # of numbers, which is 5
-10÷5=-2
The average low temperature is -2.
...which is 6th grade stuff, so I am having a hard time believing, that you are in college and/or are having problems with this.
Answer:

Step-by-step explanation:
let blank be O


54:450*100 =
(54*100):450 =
5400:450 = 12