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KiRa [710]
3 years ago
9

Based only on the giving information , it is garunteed that side AB and side CD

Mathematics
1 answer:
anastassius [24]3 years ago
6 0
May you please provide an image if possible? Thanks :)
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URGENT PLEASE ANSWER WILL GIVE BRAINLY
kicyunya [14]

Answer:

its 23xy3

Step-by-step explanation:

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3 0
3 years ago
Determine the solutuon for x^2-3x-28>0
natita [175]

Answer:

 x < -4 or x > 7.

Step-by-step explanation:

We first determine the critical points by solving x^2 - 3x - 28 = 0:

x^2 - 3x - 28 = 0

(x - 7)(x + 4) = 0

x = 7, - 4

so the critical points are  -4 and  7.

Create a Table   (pos = positive and neg = negative):

Value  of           x< - 4        -4  < x < 7         x > 7    

---------------------|----------- |--------------------- |---------------------

x + 4                  NEG           POS                 POS

x - 7                    NEG           NEG                POS

(x + 4)(x - 7)         POS           NEG                POS

So the function is positive (>0) for x < -4 or x > 7.

You can also do this by drawing the graph of the function.

6 0
3 years ago
Mathematics need help hurry and wander this question ** picture involved**
ser-zykov [4K]

Answer:

radius = 15ft

diameter = 30ft

Step-by-step explanation:

7 0
3 years ago
Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes
azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

  • The centre of the ellipse is at the origin and the X axis is the major axis

  • It passes through the points (-3, 1) and (2, -2)

<h2>To Find:</h2>

  • The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1

Given that the ellipse passes through the point (-3, 1)

Hence,

\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1

Cross multiplying we get,

  • 9b² + a² = 1 ²× a²b²
  • a²b² = 9b² + a²

Multiply by 4 on both sides,

  • 4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1

Cross multiply,

  • 4b² + 4a² = 1 × a²b²
  • a²b² = 4b² + 4a²-------(2)

Subtracting equations 2 and 1,

  • 3a²b² = 32b²
  • 3a² = 32
  • a² = 32/3----(3)

Substituting in 2,

  • 32/3 × b² = 4b² + 4 × 32/3
  • 32/3 b² = 4b² + 128/3
  • 32/3 b² = (12b² + 128)/3
  • 32b² = 12b² + 128
  • 20b² = 128
  • b² = 128/20 = 32/5

Substituting the values in the equation for ellipse,

\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1

\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>
8 0
3 years ago
I need help with math
pantera1 [17]

Answer:

answer is y=-2x

Step-by-step explanation:

-2x because every time  the dot decreases

6 0
3 years ago
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