-4(-1.5 - 9)
-4 x -1.5 = 6
-4 x 9 = -36
Answer is -30
Answer:
- The sequence is an Arthemtic Progression
An=A1+(n-1)d
A1 is first term, An is nth term, n is number of term, and d is common difference
therefore
A4=35, A1= -17
A4=A1+(4-1)d
35= -17+3d
35+17=3d
52=3d
52/3=3d/3
14=d
common diffrence(d)=14
- The general solution is given by
An= -17+(n-1)14
An= -17+14n-14
An= -31+14n
<u>An= 14n-31</u>
A14 term, means n=14
From An=A1+(n-1)d
A14= -17+(14-1)14
= -17+(13×14)
= -17+182
= 165.
<u>Therfore, the 14th term is 165.</u>
2. A sequence has a CR of 4/5 and its eighth term (a8) is (393216/3125). What is its general equation? Its 3rd term?
<u>solution</u>
common ratio(r)=4/5
eighth term(G8)=393216/3125
From Gn= G1r^(n-1)
G8 means n=8
G8=G1r^(n-1)
393216/3125=G1(4/5)^(8-1)
393216/3125=G1(4/5)^7
G1=(393216/3125)/(4/5)^7
G1=600
<u>The first term is given by G1=600</u>
The General equation is given by
The General equation is given by Gn= 600(4/5)^(n-1)
3rd term (G3)
G3= G1(4/5)^(3-1) where n=3,
=600(4/5)^2
=600(16/25)
=384
<u>Therefore, the 3rd term is given by G3= </u><u>3</u><u>8</u><u>4</u><u>.</u>
<u>I</u><u> </u><u>h</u><u>a</u><u>v</u><u>e</u><u> </u><u>m</u><u>a</u><u>d</u><u>e</u><u> </u><u>s</u><u>o</u><u>m</u><u>e</u><u> </u><u>C</u><u>o</u><u>r</u><u>r</u><u>e</u><u>c</u><u>t</u><u>i</u><u>o</u><u>n</u><u>s</u><u> </u><u>i</u><u> </u><u>m</u><u>e</u><u>s</u><u>s</u><u>e</u><u>d</u><u> </u><u>u</u><u>p</u><u> </u><u>s</u><u>o</u><u>m</u><u>e</u><u>w</u><u>h</u><u>e</u><u>r</u><u>e</u><u>.</u>
First you need to get rid of the parenthesis by distributing the 0.6 to each term inside.
(0.6)(10n) + (0.6)(25) =10+5n
6n +15 = 10+5n subtract the 5n on both sides and subtract 15 from both sides
6n-5n = 10-15
n=-5
She would have to pay $3.40 I think. A 12-pack is half the size of a 24-pack so I did half the price.
A 3d cardboard box has 6 sides, each of which are rectangles. If you unfold the 3D box, and flatten it out, then you'll be left with 6 rectangles such as what you see in the attachment below. This is one way to unfold the box. This flattened drawing is the net of the 3D rectangular prism. You can think of it as wrapping paper that covers the exterior of the box. There are no gaps or overlapping portions. If you can find the area of each piece of the net, and add up those pieces, that gets you the total area of the net. This is the exactly the surface area of the box.
In the drawing below, I've marked the sides as: top, bottom, left, right, front, back. This way you can see how the 3D box unfolds and how the sides correspond to one another. Other net configurations are possible.