3 years ago

How do you solve these types of questions?

Mathematics

1 answer:

Ahat [919]3 years ago

6 0

What questions? you didn't put any image up no one can answer your question because it's not a proper question.

You might be interested in

Find the real and imaginary zeros of the polynomial function G(x)=2-8x

kap26 [50]

For x you insert zero, and
0 = 2 - 8 * 0
0 = 2

5 0

2 years ago

What’s is the surface area of this

Marysya12 [62]

2.8 multiplied by 2.8 to find the surface area of the base which is 7.84
4*1/2*2.8*5.5 to find the surface area of all four triangular faces which is 30.8
Plus them together 7.84 plus 30.8 which is 38.64

6 0

3 years ago

Rename the fraction as a percent:1/2 =

Charra [1.4K]

1/2 = 0.5...to turn to a percent, multiply by 100.
0.5 x 100 = 50%

7 0

3 years ago

Where is 0.5 on the graph? I have to do ( 0.5, 4)

schepotkina [342]

Answer:

It would be between the 0 and the 1 on the horizontal line

0.5 is where the blue dot is, then for 0.5 , 4 just go up 4 from there

3 0

2 years ago

The longer leg of a right triangle is 6cm longer than the shorter leg and also 1cm longer than the hyptenese. find the perimeter

CaHeK987 [17]

X - a leg (x > 6);
x - 6 - a leg;
x + 1 - a <span>hypotenuse;</span>
Use the Pythagorean theorem
$(x+1)^2=x^2+(x-6)^2$

Use: $(a\pm b)^2=a^2\pm2ab+b^2$

$x^2+2x+1=x^2+x^2-12x+36\ \ \ |-x^2-2x-1\\\\x^2-14x+35=0\ \ \ |-35\\\\x^2-14x=-35\\\\x^2-2\cdot x\cdot7=-35\ \ \ |+7^2\\\\x^2-2\cdot x\cdot7+7^2=-35+7^2\\\\(x-7)^2=14\iff x-7=\pm\sqrt{14}\ \ \ |+7\\\\x=7-\sqrt{14} < 6;\ x=7+\sqrt{14}$

$x=7+\sqrt{14}\\x-6=1+\sqrt{14}\\x+1=8+\sqrt{14}$

The perimeter:

$7+\sqrt{14}+1+\sqrt{14}+8+\sqrt{14}=16+3\sqrt{14}$

5 0

3 years ago