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CaHeK987 [17]
3 years ago
9

How do you solve these types of questions?

Mathematics
1 answer:
Ahat [919]3 years ago
6 0
What questions? you didn't put any image up no one can answer your question because it's not a proper question.
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Random samples of size 81 are taken from an infinite population whose mean and standard deviation are 200 and 18, respectively.
TiliK225 [7]

Answer:

d. 200 and 2

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

Mean = 200

Standard deviation = 18

Sample size: 81

Standard error: s = \frac{18}{\sqrt{81}} = 2

So the correct answer is:

d. 200 and 2

7 0
3 years ago
Read 2 more answers
Can someone help me with this please? :)))​
Natali5045456 [20]

Answer:

88

Step-by-step explanation:

86 is 98% of 87.755102040816 which rounded to the nearest whole number is 88.

7 0
2 years ago
Read 2 more answers
Which graph shows the points (−112, 12) and (1.5, −0.5) plotted correctly? On a coordinate plane, a point is 0.5 units to the ri
chubhunter [2.5K]

Answer:

Graph 'B' represents the correct graph.

The correct graph is attached below.

Step-by-step explanation:

Let 'A' be the point:

  • A\left(-1\frac{1}{2},\:\frac{1}{2}\right)

Let 'B' be the point:

  • B\:\left(1.5,\:-0.5\right)

As point A(-1 1/2, 1/2) can be written as:

A=\left(-\frac{3}{2},\:\frac{1}{2}\right)=\left(-1.5,\:0.5\right)

so plotting the point A=\left(-1.5,\:0.5\right)\:\:\:\: and B\:\left(1.5,\:-0.5\right) on a B\:\left(1.5,\:-0.5\right).

  • As we know that the 2nd quadrant, in the upper left-hand corner, consists of negative values of x and positive values of y.

Thus, the point A(-1.5, 0.5) will be plotted in the 2nd quadrant at x = -1.5 and y=0.5

i.e. at x= -1.5, y = 0.5

  • As we know that the 4th quadrant, the lower left-hand corner, consists of positive values of x and negative values of y.

Point B(1.5, -0.5) will be plotted in the 4th quadrant at x = 1.5 and y = -0.5

i.e. at x= 1.5, y = -0.5

Thus, graph 'B' represents the correct graph.

The correct graph is attached below.

6 0
3 years ago
Read 2 more answers
If the half-life of aspirin in the bloodstream is 5 hours, how much aspirin is left in the bloodstream 12 hours after 1000 milli
Tom [10]

\bf \textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1000\\ t=\textit{elapsed time}\dotfill &12\\ h=\textit{half-life}\dotfill &5 \end{cases} \\\\\\ A=1000\left( \frac{1}{2} \right)^{\frac{12}{5}}\implies A\approx 1000\cdot 0.189\implies A\approx 189

8 0
3 years ago
If f(x) = 4, then x
vampirchik [111]

Answer:

x=4/f

Step-by-step explanation:

6 0
2 years ago
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