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3 years ago

How do you solve these types of questions?

Mathematics

1 answer:

Ahat [919]3 years ago

6 0

What questions? you didn't put any image up no one can answer your question because it's not a proper question.

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Random samples of size 81 are taken from an infinite population whose mean and standard deviation are 200 and 18, respectively.

TiliK225 [7]

Answer:

d. 200 and 2

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

Mean = 200

Standard deviation = 18

Sample size: 81

Standard error: $s = \frac{18}{\sqrt{81}} = 2$

So the correct answer is:

d. 200 and 2

7 0

3 years ago

Read 2 more answers

Can someone help me with this please? :)))

Natali5045456 [20]

Answer:

Step-by-step explanation:

86 is 98% of 87.755102040816 which rounded to the nearest whole number is 88.

7 0

2 years ago

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Which graph shows the points (−112, 12) and (1.5, −0.5) plotted correctly? On a coordinate plane, a point is 0.5 units to the ri

chubhunter [2.5K]

Answer:

Graph 'B' represents the correct graph.

The correct graph is attached below.

Step-by-step explanation:

Let 'A' be the point:

$A\left(-1\frac{1}{2},\:\frac{1}{2}\right)$

Let 'B' be the point:

$B\:\left(1.5,\:-0.5\right)$

As point A(-1 1/2, 1/2) can be written as:

$A=\left(-\frac{3}{2},\:\frac{1}{2}\right)=\left(-1.5,\:0.5\right)$

so plotting the point $A=\left(-1.5,\:0.5\right)\:\:\:\:$ and $B\:\left(1.5,\:-0.5\right)$ on a $B\:\left(1.5,\:-0.5\right)$ .

As we know that the 2nd quadrant, in the upper left-hand corner, consists of negative values of x and positive values of y.

Thus, the point A(-1.5, 0.5) will be plotted in the 2nd quadrant at x = -1.5 and y=0.5

i.e. at x= -1.5, y = 0.5

As we know that the 4th quadrant, the lower left-hand corner, consists of positive values of x and negative values of y.

Point B(1.5, -0.5) will be plotted in the 4th quadrant at x = 1.5 and y = -0.5

i.e. at x= 1.5, y = -0.5

Thus, graph 'B' represents the correct graph.

The correct graph is attached below.

6 0

3 years ago

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If the half-life of aspirin in the bloodstream is 5 hours, how much aspirin is left in the bloodstream 12 hours after 1000 milli

Tom [10]

$\bf \textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1000\\ t=\textit{elapsed time}\dotfill &12\\ h=\textit{half-life}\dotfill &5 \end{cases} \\\\\\ A=1000\left( \frac{1}{2} \right)^{\frac{12}{5}}\implies A\approx 1000\cdot 0.189\implies A\approx 189$

8 0

3 years ago

If f(x) = 4, then x

vampirchik [111]

Answer:

x=4/f

Step-by-step explanation:

6 0

2 years ago