Sub those points for x
f(x) is the y
(x,y)
so for x=0
f(0)=2(0)^4+3
f(0)=0+3
f(0)=3
(0,3) is a opint
for x=1
f(1)=2(1)^4+3
f(1)=2(1)+3
f(1)=2+3
f(1)=5
(1,5) is another point
for x=2
f(2)=2(2^4)+3
f(2)=2(16)+3
f(2)=32+3
f(2)=35
(2,35) is another point
points are
(0,3)
(1,5)
(2,35)
Firstly,
thanks for posting this.
81 = 9x9 or 9 squared so at this stage I'm guessing the last two.
x^ 8 = (x^ 4) x (x^ 2) (its called the multiplication rule of indices).
Okay I have approx 14 mins to answer.
No panic
√ 81.x^8 x <span>√ y^5
</span>√ (9x^2 x 9x^6) x <span>√ y^5
</span>= 9x x <span>√ 9x^6 x </span><span>√ y^5
</span>did I just gain time?
√ 9x^6 = <span>√ </span>3x ^3 x <span>√ 3x ^ 3
</span>or 2 . √ 3x^3. <span>√ y^5
</span>more time
okay, so that wasnt successful.
√ 9x^6 =<span>√ </span> (3x^2) x <span>√ </span>(3x^4)
A = a^2.....where " a " is the length of one side
A = 79
79 = a^2...take sqrt of both sides, eliminating the ^2
sqrt 79 = a
8.89 = a
so the length of one side is approximately 8.89 ft <==
21) 3(2j-k)=108 It is asking you to set the equation equal to j
distribute the 3
6j-3k=108
move k to the other side by adding on both sides
6j=108+3k
divide everything by 6
j=18+0.5k
Answer:
Step-by-step explanation:
perpendicular (P) = 6
base (b) = 8
hypotenuse (h) =?
we know by using Pythagoras theorem,
h = 
= 
= 10
