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vladimir1956 [14]
4 years ago
10

Find the length of the diagonal of a square with perimeter of 24

Mathematics
1 answer:
julsineya [31]4 years ago
8 0

Answer:

d = 6sqrt(2) or 8.4853

Step-by-step explanation:

<u><em>Formula</em></u>

P = 4*s

s^2 + s^2 = d^2 where d is the diagonal and s is the side.

<u><em>Givens</em></u>

P = 24

<u><em>Solution</em></u>

P = 4s         Substitute for s

24 = 4*s      Divide by 4

24/4 = s

s = 6

================

d^2 = s^2 + s^2

d^2 = 6^2 + 6^2

d^2 = 36 + 26

d^2 = 72

d = sqrt(72)

Factors of 72

72: 6 * 6 * 2

<em><u>Rule</u></em>: Every pair of = factors allows you to take one of them outside the sqrt sign and throw the other a way. If there are no pairs, whatever you started with stays under the root sign.

sqrt(6*6*2) = 6sqrt(2)

  • The diagonal length is either
  • d = 6*sqrt(2) or
  • d = 8.4853

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George and Riley are selling fruit for a school fundraiser. Customers can buy small boxes of oranges and large boxes of oranges.
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The cost of small box of oranges is $7.

The cost of large box of oranges is $13.

<u>Step-by-step explanation:</u>

It is given that,

3 small boxes of oranges and 14 large boxes of oranges for a total of $203.

11 small boxes of oranges and 11 large boxes of oranges for a total of $220.

Let us take,

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  • The cost of large box of oranges = y

<u>The system of equations are framed as :</u>

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Multiply equation (1) by 11 and equation (2) by 3

Subtract eq(2) from eq(1),

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⇒ y = 1573 / 121

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∴ The cost of large box of oranges is $13.

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⇒ 3x + 14(13) = 203

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⇒ 3x = 203 - 182

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⇒ x = 21 / 3

⇒ x = 7

∴ The cost of small box of oranges is $7.

<u />

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