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riadik2000 [5.3K]
3 years ago
13

3/2:5/7=12/5:x solve for X

Mathematics
2 answers:
Natali5045456 [20]3 years ago
7 0
Cross multiplying

=> 3x /2 = 12/7
=> 7x = 8
=>  x =8/7

hope it helped a bit
Artyom0805 [142]3 years ago
3 0
(5/7)/(3/2)=x/(12/5)

(5/7)(2/3)=x(5/12)

10/21=5x/12

5x=120/21

x=120/105

x=24/21

x=8/7
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3 years ago
Mrs.Storz is driving at 48.5 mph for 1.2 hours. What will be the distance travelled by Mrs.Storz?
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Answer:

58.2

Step-by-step explanation:

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3 years ago
a leatherback turtle swims at a constant rate of 2.5 kilometers per hour, at its constant rate of speed how long will it take fo
LekaFEV [45]
Hello there!

So, if this turtle is only going 2.5 miles per hour. This would mean that (EACH) hour, this turtle only arrived 2.5 miles. So, we do,

\boxed{10.0 \left \{ {{2.5+2.5=5.0} \atop {2.5+2.5=5.0}} \right.}

We would have to count how many ("2.5's" they are above.)

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5 0
4 years ago
At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric
Zanzabum

Answer:

a) (1215, 1297)

b) (1174,  1338)

c) (1133, 1379)      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

Standard Deviation, σ = 41

Empirical Rule:

  • Also known as 68-95-99.7 rule.
  • It states that almost all the data lies within three standard deviation for a normal data.
  • About 68% of data lies within 1 standard deviation of mean.
  • About 95% of data lies within two standard deviation of mean.
  • About 99.7% of data lies within 3 standard deviation of mean.

a) range of years centered about the mean in which about 68% of the data lies

\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)

68% of data will be found between 1215 years and 1297 years.

b) range of years centered about the mean in which about 95% of the data lies

\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)

95% of data will be found between 1174 years and 1338 years.

c) range of years centered about the mean in which about all of the data lies

\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)

All of data will be found between 1133 years and 1379 years.

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