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3 years ago

Use mathematical

Mathematics

1 answer:

sdas [7]3 years ago

7 0

Answer:

This is a pretty broad question but im guessing you could use math to calculate how many people would get infected each day. You could start with

Ex.

Okay if we have one infected person how many people could they possibly pass the illness onto the next day. Well if they have x number of classes and see y number of people in those classes whats the PROBABILIITY one of those people gets the virus. Than you could calculate how many people will get infected the NEXT day.

You might be interested in

Evaluate |3x| +4 when x=-5

Harlamova29_29 [7]

I think the answer is 19

5 0

3 years ago

a store sign reads take 75% off the original price when you take an additional 15% off the sale price which is 60% off the regul

Lelu [443]

I you take 75% off the original price, 25% remains.

If you take 60% off the original price, 40% remains. Taking 15% off that means you take off an additional 0.15*40% = 6% of the original price, so end up with
40% -6% = 34%
of the original price. This is considerably more than 25% of the original price.

The store sign is not accurate, because the "additional 15%" is of the sale price, not the original price.

4 0

3 years ago

At a graduation ceremony, some students earned bachelors in science degrees, some earned bachelors in arts degrees, and some stu

dedylja [7]

Answer:80students

Step-by-step explanation:

Using set notation concept,

n(U) be the total number of student = 200

n(AnS') be those that earned Bachelor in Art only= 120

n(A'nS) be those that earned Bachelor in Science only= 40

n(AnS) be students that earned both degrees.

Using the formulae below to calculate n(AnS) first;

n(AuS)=n(A'nS)+ n(AnS)+n(AnS')

200=40+n(AnS)+120

200=160+n(AnS)

n(AnS)=40

This shows that 40students earned bachelor in both degrees

Those that earned Bachelor in science degree will then be n(A'nS)+n(AnS) i.e 40+40 =80students.

NB: A' means complement of A(A not included)

'n' denote intersection and 'u' denote union.

7 0

4 years ago

I really need help on gradpoint I will mark you braniliest

insens350 [35]

Answer: I’ll say B. Infinity many solutions

Explanation: it’s just a guess sorry if I’m wrong ^_^

4 0

3 years ago

Consider the following information: Tony, Mike, and John belong to the Alpine Club. Every member of the Alpine club who is not a

zzz [600]

Answer:

ranslation into first order logic ,

Tony, Mike and John belong to Alpine club.

S1 Member (Tony)

S2 Member (mike)

S3 Member (john)

Every member of the Alpine club who is not a skier is a mountain climber

S4 \forallx(Member(x)\wedge~Skier(x)\supsetClimber(x))

Mountain climbers do not like rain

S5 \forallx(Climber(x) \supset ~Like(x,Rain))

Anyone who does not like snow is not a skier

S6 \forallx(~Like(x,snow) \supset ~ Skier(x))

Mike dislikes whatever Tony likes

S7 \forallx(Like(Tony,x) \supset ~ Like(mike,x))

And likes whatever Tony dislikes

S8 \forallx(~Like(Tony,x) \supset Like(Mike,x)

Tony likes rain and snow

S9 Like(Tony,rain)

S10 Like(Tony, snow)

From s10 we know that (I(tony),I(snow)) \in I(Like)

From s7 we know that for every assignment v

(D,I),v|= Like(tony,x)\supset ~Like(Mike,x)

(D,I),v|= Member(x) \wedge Climber(x) \wedge ~ Skier(x)

(D,I),v |= \existsx(Member(x)\wedgeClimber(x)\wedge~Skier(x))

Hence a member of Alpine club who is a mountain climber but not a skier

suppose we donot have S7 , we have only s1-s6 and s8-s10.

To prove , we have to produce interpretations as :

D ={ t,m,j,s,r }

Interpretations:

I(tony)=t, I(mike)=m, I(john)=j, I(snow)=s, I(rain)=r

I(member)= {t,m,j}

I(skier)= {t,m,j}

I(climber)= {}

I(Like)= {(t,s),(t,r),(m,s),(m,r),(m,m),(m,t),(m,j),(j,s)}

Hence a member of Alpine club who is a mountain climber but not a skier

4 0

4 years ago