Starting equation:
92=J+L+B
To find how much money Jane has, we use the equation:
J=5+3L
To find how much money Bob has, we use the equation:
B=4L-1
Enter those equations in the problem
92=(5+3L)+L+(4L-1)
Combine like terms
92=4+8L
Subtract 4 to isolate variable
88=8L
Divide by 8 to isolate variable
11=L
Answer:
Lonnie has $11
Jane has $38
Bob has $43
side note: Lonnie is that one poor friend we all have
I feel like it’s 180 dregrees, good luck!
Answer:
The hypotheses used in this situation


Step-by-step explanation:
We are given that Business Week reported that at the top 50 business schools, students studied an average of 14.6 hours.
Mean = 
Claim : The amount UMSL students study is different from this 14.6 hour benchmark.
The hypotheses used in this situation


If <em>x</em>² + <em>y</em>² = 1, then <em>y</em> = ±√(1 - <em>x</em>²).
Let <em>f(x)</em> = |<em>x</em>| + |±√(1 - <em>x</em>²)| = |<em>x</em>| + √(1 - <em>x</em>²).
If <em>x</em> < 0, we have |<em>x</em>| = -<em>x</em> ; otherwise, if <em>x</em> ≥ 0, then |<em>x</em>| = <em>x</em>.
• Case 1: suppose <em>x</em> < 0. Then
<em>f(x)</em> = -<em>x</em> + √(1 - <em>x</em>²)
<em>f'(x)</em> = -1 - <em>x</em>/√(1 - <em>x</em>²) = 0 → <em>x</em> = -1/√2 → <em>y</em> = ±1/√2
• Case 2: suppose <em>x</em> ≥ 0. Then
<em>f(x)</em> = <em>x</em> + √(1 - <em>x</em>²)
<em>f'(x)</em> = 1 - <em>x</em>/√(1 - <em>x</em>²) = 0 → <em>x</em> = 1/√2 → <em>y</em> = ±1/√2
In either case, |<em>x</em>| = |<em>y</em>| = 1/√2, so the maximum value of their sum is 2/√2 = √2.
Answer:
187.5
Step-by-step explanation:
12 × 2.5 × 6.25 = 187.5