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3 years ago

How do I find domain and the range on a graph ?

1 answer:

7 0

Domain is the possible values of inputs range is the possible values of outputs. For the function y = 1/x, for instance, the domain is (-∞,0)∪(0,∞) since 1/0 is undefined, and the range is (-∞,0)∪(0,∞).

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Please help me with this!! Number 6 is the problem

artcher [175]

The first two consecutive odd integers are 1 and 3.
The height has to be 3 since the question implies that the height is exceeds the base. So the base is 1. b = 1 cm

The area of a triangle is base*height*(1/2)
Plug in the values for base and height.
1*3*(1/2)

Simplify. Your final answer should be 1.5 cm^2

8 0

3 years ago

Consider the function f(x)=x3+15x2+74x+120. If f(x)=0 for x=−6, for what other values of x is the function equal to 0? List the

jasenka [17]

Answer:

other x values are -5,-4

Step-by-step explanation:

f(x)=0 for x=−6

Apply synthetic division to get the quotient . using that we find other two values of x

-6 1 15 74 120

0 -6 - 54 -120

-------------------------------------------------

1 9 20 0

the quotient is $x^2+9x+20=0$

now factor the left hand side, product is 20 and sum is 9

$x^2+9x+20=0\\(x+5)(x+4)=0\\x+5=0 , x=-5\\x+4=0, x=-4$

So other x values are -5,-4

8 0

3 years ago

A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on

SVEN [57.7K]

Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± $Z_{1-\alpha /2}$ * $\frac{S}{\sqrt{n} }$

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

$Z_{1-\alpha /2}= Z_{0.95}= 1.645$

[10.41±1.645* $(\frac{3.71}{\sqrt{28} } )$ ]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

I hope this helps!

7 0

3 years ago

Find the largest number which divides 149 and 101 , leaving remainder of 5

erik [133]

The answer to this problem is 48.

8 0

3 years ago

6x^2y^3/3xy 6x squared times y cubed divided by 3xy simplify

Lera25 [3.4K]

Answer:

$2xy^2$