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ivann1987 [24]
3 years ago
8

Help me please,Thanks

Mathematics
1 answer:
choli [55]3 years ago
8 0

Area of a triangle=1/2b8h(1/2times base times height)

1/2(12)*(10)=60.

Area of the  window is 60

And I hope that helps you

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a total eclipse in 2003 lasted 2 17/24,minutes in 2005 it lasted 3/8 of a minute how much longer did it last in 2003
Doss [256]

Answer:

Total eclipse was 2\frac{1}{3} minutes longer than in 2005.

Step-by-step explanation:

It is given in the question that total eclipse in 2003 lasted 2\frac{17}{24} minutes and in 2005 it lasted 3/8 of a minute.

We have to calculate how much longer did it last in 2003.

So we have to subtract the duration in 2003 by duration in 2005

Total time taken in 2003- total time taken in 2005

=2\frac{17}{24}-\frac{3}{8}

\frac{48+17}{24}-\frac{3}{8}

=\frac{65}{24}-\frac{3}{8}

=\frac{65-9}{24}

=\frac{56}{24}

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=2\frac{1}{3} minutes


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4 years ago
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3 years ago
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1. 15

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