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2 years ago

Can you help me with this question

Mathematics

1 answer:

Hatshy [7]2 years ago

6 0

Square root = exponent to power 1/2

sqrt(20x^6y^7)
= (20x^6y^7)^1/2
= 20^1/2 x^3 y^(7/2)

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What is the domain of a function?

Katen [24]

B . The set of all first elements of the function is the answer

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3 years ago

What type of angle is

mash [69]

Answer:

I'm really sorry I can't tell you the answer because you have to measure the angle by yourself using a protractor. But I gave you information about types of angles if you got the degree of angles ( e.g 90 degrees). Hope it helped.

Step-by-step explanation:

acute angle-an angle between 0 and 90 degrees

right angle-an 90 degree angle

obtuse angle-an angle between 90 and 180 degrees

straight angle-a 180 degree angle

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3 years ago

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which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1

lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. $y=\sec x$

B. $y= \tan x$

C. $y= \cot x$

D. $y= \csc x$

Answer:

A. $y=\sec x$

D. $y=\csc x$

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: $y=\sec x$

We know that, the $\sec x=\frac{1}{\cos x}$

The range of $\cos x$ is from -1 to 1 given as [-1, 1]. So,

$|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the secant function as:

$\sec x\leq -1\ or\ \sec x\geq 1\\$

Therefore, the range of $y=\sec x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

Choice B: $y= \tan x$

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: $y= \cot x$

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: $y=\csc x$

We know that, the $\csc x=\frac{1}{\sin x}$

The range of $\sin x$ is from -1 to 1 given as [-1, 1]. So,

$|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

$\csc x\leq -1\ or\ \csc x\geq 1\\$

Therefore, the range of $y=\csc x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

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3 years ago

Find the cosine 315º. Round your answers to the nearest hundredth if necessary. 0 0.71 1 –0.78

Fofino [41]

Cos 315° is about 0.71.

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3 years ago

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3.3x10^-3 in standard notation

const2013 [10]

First you do the exponents so 10^-3 is:

1/10^3 (change it so it is not a negative exponent, so make it its reciprocal)

1/(10*10*10) = 1/1000 = 0.001

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3 years ago