the complete question is
Find two numbers whose difference is 46 and whose product is a minimum
Let
x------->larger number
y-------> smaller number
P-------> product of the two numbers
we know that
-----> equation 1
-----> equation 2
substitute equation 1 in equation 2
![P=x*[x-46]\\ P=x^{2} -46x](https://tex.z-dn.net/?f=%20P%3Dx%2A%5Bx-46%5D%5C%5C%20P%3Dx%5E%7B2%7D%20-46x%20)
using a graph tool
see the attached figure
Find the value of x for that the product P is a minimum
the vertex is the point 
that means, for 
the product is a minimum 
find the value of y
therefore
the answer is
the numbers are 
and 
Answer:
-2
Step-by-step explanation:
5 + (-7)
5 - 7
-2
Please let me know if something's wrong!
well, we know the common difference is -3, to go from the 4th term to the 8th term, we need to add "d" 4 times or namely 3+4(-3), likewise to go from the 13th term to the 19th term we have to add "d" 6 times, or namely -24 + 6(-3).
Answer:
y= -10x + 5
Step-by-step explanation:
i did some math
Answer: See explanation
Step-by-step explanation:
1. ∠WOV and m∠30° are complementary angles so they should add up to 90°
∠WOV + 30 = 90
Subtract 30 from both sides
∠WOV = 60°
I used the relationship of complementary angles.
2. ∠YOZ and ∠WOV are vertical angles so they're congruent.
∠YOZ ≅ ∠WOV
∠YOZ ≅ 60°
∠YOZ = 60°
I used the relationship of vertical angles.
I hope this helped!
